Basically I want to upload an image (which i've sorted) and scale it down to certain constraints such as max width and height but maintain the aspect ratio of the original image.
I don't have Imagick installed on the server - otherwise this would be easy.
Any help is appreciated as always. Thanks.
EDIT: I don't need the whole code or anything, just a push in the right direction would be fantastic.
Press-and-hold the Shift key, grab a corner point, and drag inward to resize the selection area. Because you're holding the Shift key as you scale, the aspect ratio (the same ratio as your original photo) remains exactly the same.
The imagescale() function is an inbuilt function in PHP which is used to scale an image using the given new width and height. Parameters: This function accepts four parameters as mentioned above and described below: $image: It is returned by one of the image creation functions, such as imagecreatetruecolor().
Actually the accepted solution it is not the correct solution. The reason is simple: there will be cases when the ratio of the source image and the ratio of the destination image will be different. Any calculation should reflect this difference.
Please note the relevant lines from the example given on PHP.net website:
$ratio_orig = $width_orig/$height_orig; if ($width/$height > $ratio_orig) { $width = $height*$ratio_orig; } else { $height = $width/$ratio_orig; }
The full example may be found here: http://php.net/manual/en/function.imagecopyresampled.php
There are other answers (with examples) on stackoverflow to similar questions (the same question formulated in a different manner) that suffer of the same problem.
Example:
Let's say we have an image of 1630 x 2400 pixels that we want to be auto resized keeping the aspect ratio to 160 x 240. Let's do some math taking the accepted solution:
if($old_x < $old_y) { $thumb_w = $old_x*($new_width/$old_y); $thumb_h = $new_height; }
height = 240 width = 1630 * ( 160/2400 ) = 1630 * 0.0666666666666667 = 108.6666666666667 108.6 x 240 it's not the correct solution.
The next solution proposed is the following:
if($old_x < $old_y) { $thumb_w = $old_x/$old_y*$newHeight; $thumb_h = $newHeight; }
height = 240; width = 1630 / 2400 * 240 = 163 It is better (as it maintain the aspect ratio), but it exceeded the maximum accepted width.
Both fail.
We do the math according to the solution proposed by PHP.net: width = 160 height = 160/(1630 / 2400) = 160/0.6791666666666667 = 235.5828220858896 (the else clause). 160 x 236 (rounded) is the correct answer.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With