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Scala Immutable MultiMap

In Scala I would like to be able to write

val petMap = ImmutableMultiMap(Alice->Cat, Bob->Dog, Alice->Hamster)

The underlying Map[Owner,Set[Pet]] should have both Map and Set immutable. Here's a first draft for ImmutibleMultiMap with companion object:

import collection.{mutable,immutable}

class ImmutableMultiMap[K,V] extends immutable.HashMap[K,immutable.Set[V]]

object ImmutableMultiMap {
  def apply[K,V](pairs: Tuple2[K,V]*): ImmutableMultiMap[K,V] = {
    var m = new mutable.HashMap[K,mutable.Set[V]] with mutable.MultiMap[K,V]
    for ((k,v) <- pairs) m.addBinding(k,v)
    // How do I return the ImmutableMultiMap[K,V] corresponding to m here?
  }
}

Can you resolve the comment line elegantly? Both the map and the sets should become immutable.

Thanks!

like image 232
PerfectTiling Avatar asked Aug 07 '10 18:08

PerfectTiling


People also ask

What is Scala MultiMap?

trait MultiMap[A, B] extends Map[A, Set[B]] A trait for mutable maps with multiple values assigned to a key. This class is typically used as a mixin. It turns maps which map A to Set[B] objects into multimaps that map A to B objects.

Are Scala maps immutable?

There are two kinds of Maps, the immutable and the mutable. The difference between mutable and immutable objects is that when an object is immutable, the object itself can't be changed. By default, Scala uses the immutable Map. If you want to use the mutable Map, you'll have to import scala.

How can we convert mutable to immutable Scala?

Generally, from mutable to immutable, you use the to* series methods in mutable collections, like MutableList and ListBuffer's toList method. In the other hand, from immutable to mutable, you can just use constructors like this: scala. collection. mutable.


2 Answers

I've rewritten this same method twice now, at successive jobs. :) Somebody Really Oughta make it more general. It's handy to have a total version around too.

  /**
   * Like {@link scala.collection.Traversable#groupBy} but lets you return both the key and the value for the resulting
   * Map-of-Lists, rather than just the key.
   *
   * @param in the input list
   * @param f the function that maps elements in the input list to a tuple for the output map.
   * @tparam A the type of elements in the source list
   * @tparam B the type of the first element of the tuple returned by the function; will be used as keys for the result
   * @tparam C the type of the second element of the tuple returned by the function; will be used as values for the result
   * @return a Map-of-Lists
   */
  def groupBy2[A,B,C](in: List[A])(f: PartialFunction[A,(B,C)]): Map[B,List[C]] = {

    def _groupBy2[A, B, C](in: List[A],
                           got: Map[B, List[C]],
                           f: PartialFunction[A, (B, C)]): Map[B, List[C]] =
    in match {
      case Nil =>
        got.map {case (k, vs) => (k, vs.reverse)}

      case x :: xs if f.isDefinedAt(x) =>
        val (b, c) = f(x)
        val appendTo = got.getOrElse(b, Nil)
        _groupBy2(xs, got.updated(b, c :: appendTo), f)

      case x :: xs =>
        _groupBy2(xs, got, f)
    }

    _groupBy2(in, Map.empty, f)
  }

And you use it like this:

val xs = (1 to 10).toList
groupBy2(xs) {
  case i => (i%2 == 0, i.toDouble)
}   

res3: Map[Boolean,List[Double]] = Map(false -> List(1.0, 3.0, 5.0, 7.0, 9.0),       
                                      true -> List(2.0, 4.0, 6.0, 8.0, 10.0)) 
like image 128
Alex Cruise Avatar answered Sep 29 '22 02:09

Alex Cruise


You have a bigger problem than that, because there's no method in ImmutableMultiMap that will return an ImmutableMultiMap -- therefore it is impossible to add elements to it, and the constructor does not provide support for creating it with elements. Please see existing implementations and pay attention to the companion object's builder and related methods.

like image 45
Daniel C. Sobral Avatar answered Sep 29 '22 00:09

Daniel C. Sobral