Save print screen in C#

Question

Bitmap bitmap = new Bitmap(Screen.PrimaryScreen.Bounds.Width, 
                                    Screen.PrimaryScreen.Bounds.Height);
Graphics graphics = Graphics.FromImage(bitmap as Image);
graphics.CopyFromScreen(0, 0, 0, 0, bitmap.Size);
bitmap.Save(@"C:\Temp\printscreen.jpg", ImageFormat.Jpeg);

This is my code for print screen button. The problem is that I press the button few times and it just write over the old image file (printscreen.jpg), it will not create another new image file such as printscreen1.jpg.

Answer 1

Try this. It will generate a unique file each time.

Bitmap bitmap = new Bitmap(Screen.PrimaryScreen.Bounds.Width, 
                                    Screen.PrimaryScreen.Bounds.Height);
Graphics graphics = Graphics.FromImage(bitmap as Image);
graphics.CopyFromScreen(0, 0, 0, 0, bitmap.Size);
bitmap.Save(@"C:\Temp\printscreen"+Guid.NewGuid()+".jpg", ImageFormat.Jpeg);

OR

Bitmap bitmap = new Bitmap(Screen.PrimaryScreen.Bounds.Width, 
                                    Screen.PrimaryScreen.Bounds.Height);
Graphics graphics = Graphics.FromImage(bitmap as Image);
graphics.CopyFromScreen(0, 0, 0, 0, bitmap.Size);
var date = DateTime.Now.ToString("MMddyyHmmss");
bitmap.Save(@"C:\Temp\printscreen"+date+".jpg", ImageFormat.Jpeg);

Answer 2

it will not create another new image file

You are not asking it to create one, your code

bitmap.Save(@"C:\Temp\printscreen.jpg", ImageFormat.Jpeg);

is always writing to the same file.

new image file such as printscreen1.jpg

If you want to create a new file, you need to generate your filename dynamically. Something like

 string fileName = System.IO.Path.GetTempPath() + DateTime.Now.ToString() + ".jpg";
 bitmap.Save(fileName, ImageFormat.Jpeg);