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Sass color variable not working inside darken()

Tags:

sass

I've got list of colors and I would like to use darken() on them like so:

$innerPagesBgColors: "#6B46C1", "#2980B9", "#FD5456", "#000";

.foo {
    color: darken(nth($innerPagesBgColors, 3), 5%);
}

But I get this error:

$color: "#FD5456" is not a color for `darken'

I tried interpolating the nth() portion but that didn't help either.

like image 631
user1477567 Avatar asked Dec 12 '13 05:12

user1477567


1 Answers

The problem is that darken function requires a color as first argument and, instead, you're trying to pass a string.

type-of(#6B46C1); // returns color
type-of("#6B46C1"); // returns string

So you should remove all quotes in $innerPagesBgColors:

$innerPagesBgColors: #6B46C1, #2980B9, #FD5456, #000;
like image 51
Alex Guerrero Avatar answered Sep 28 '22 06:09

Alex Guerrero