I want to do 10-fold cross-validation for huge files ( running into hundreds of thousands of lines each). I want to do a "wc -l " each time i start reading a file, then generate random numbers a fixed number of times, each time writing that line number into a separate file . I am using this:
import os
for i in files:
os.system("wc -l <insert filename>").
How do I insert the file name there. Its a variable. I went through the documentation but they mostly list out ls
commands, something that doesn't have this problem.
Let's compare:
from subprocess import check_output
def wc(filename):
return int(check_output(["wc", "-l", filename]).split()[0])
def native(filename):
c = 0
with open(filename) as file:
while True:
chunk = file.read(10 ** 7)
if chunk == "":
return c
c += chunk.count("\n")
def iterate(filename):
with open(filename) as file:
for i, line in enumerate(file):
pass
return i + 1
Go go timeit function!
from timeit import timeit
from sys import argv
filename = argv[1]
def testwc():
wc(filename)
def testnative():
native(filename)
def testiterate():
iterate(filename)
print "wc", timeit(testwc, number=10)
print "native", timeit(testnative, number=10)
print "iterate", timeit(testiterate, number=10)
Result:
wc 1.25185894966
native 2.47028398514
iterate 2.40715694427
So, wc is about twice as fast on a 150 MB compressed files with ~500 000 linebreaks, which is what I tested on. However, testing on a file generated with seq 3000000 >bigfile
, I get these numbers:
wc 0.425990104675
native 0.400163888931
iterate 3.10369205475
Hey look, python FTW! However, using longer lines (~70 chars):
wc 1.60881590843
native 3.24313092232
iterate 4.92839002609
So conclusion: it depends, but wc seems to be the best bet allround.
import subprocess
for f in files:
subprocess.call(['wc', '-l', f])
Also have a look at http://docs.python.org/library/subprocess.html#convenience-functions - for example, if you want to access the output in a string, you'll want to use subprocess.check_output()
instead of subprocess.call()
Here is a Python approach I found to solve this problem:
count_of_lines_in_any_textFile = sum(1 for l in open('any_textFile.txt'))
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