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I have 3 threads 1st printing A 2nd printing B 3rd printing C
I want to print in sequence A B C A B C A B C and so on.....
So I wrote the program below, but I am not able to achieve the same. I am aware of the problem that when status=1 at that time say for example B1 and C1 thread are waiting and when I do notifyAll() both waiting thread wake up and depending on CPU allocation it might print B or C.
in this case I want only B to be printed after A.
what modification I need to do.
public class NotifyAllExample {
int status=1;
public static void main(String[] args) {
NotifyAllExample notifyAllExample = new NotifyAllExample();
A1 a=new A1(notifyAllExample);
B1 b=new B1(notifyAllExample);
C1 c=new C1(notifyAllExample);
a.start();
b.start();
c.start();
}
}
class A1 extends Thread{
NotifyAllExample notifyAllExample;
A1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
@Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=1){
notifyAllExample.wait();
}
System.out.print("A ");
notifyAllExample.status = 2;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println("Exception 1 :"+e.getMessage());
}
}
}
class B1 extends Thread{
NotifyAllExample notifyAllExample;
B1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
@Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=2){
notifyAllExample.wait();
}
System.out.print("B ");
notifyAllExample.status = 3;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println("Exception 2 :"+e.getMessage());
}
}
}
class C1 extends Thread{
NotifyAllExample notifyAllExample;
C1(NotifyAllExample notifyAllExample){
this.notifyAllExample = notifyAllExample;
}
@Override
public void run() {
try{
synchronized (notifyAllExample) {
for (int i = 0; i < 100; i++) {
if(notifyAllExample.status!=3){
notifyAllExample.wait();
}
System.out.print("C ");
notifyAllExample.status = 1;
notifyAllExample.notifyAll();
}
}
}catch (Exception e) {
System.out.println("Exception 3 :"+e.getMessage());
}
}
}
650
In order to create a thread, first we need to create an Instance of RunnableWorker which implements the runnable interface. The above code creates a runnable instance r. Then it create 3 threads (t1, t2 and t3) and passes r as the argument to the 3 threads. Then the start() function is used to start all 3 threads.
When multiple threads are based on the same object of a class that has implemented Runnable interface or extended Thread class, a synchronized run of these multiple threads can be achieved just by marking the implemented run() method with synchronized keyword.
Convert those IF statements to WHILE statements to get the desired behavior:
if (notifyAllExample.status != 2){
notifyAllExample.wait();
}
to
while (notifyAllExample.status != 2){
notifyAllExample.wait();
}
This will ensure that if a thread is notified, it won't go out of the while loop until the status value is what it expects.
Also, mark status as volatile so that the threads won't have a local copy.
157
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