Run mocha excluding paths

Question

I have this (in gulpfile.js):

var gulp = require("gulp"); var mocha = require("gulp-mocha"); gulp.task("test", function() {     gulp         .src(["./**/*_test.js", "!./node_modules/**/*.js"]); }); 

and it works.

I want to replicate the same behavior, excluding "node_modules" folder, from mocha command, running npm test (in package.json):

"scripts": {     "test": "mocha **\\*_test.js !./node_modules/**/*.js*", } 

and it doesn't work.

I'm using Windows.

Any suggestion?

Answer 1

I was able to solve this using globbing patterns in the argument to mocha. Like you I didn't want to put all my tests under a single tests folder. I wanted them in the same directory as the class they were testing. My file structure looked like this:

project |- lib    |- class1.js    |- class1.test.js |- node_modules    |- lots of stuff... 

Running this from the project folder worked for me:

mocha './{,!(node_modules)/**}/*.test.js' 

Which match any *.test.js file in the tree, so long is its path isn't rooted at ./node_modules/.

This is an online tool for testing glob patterns that I found useful.

Answer 2

You can exclude files in mocha by passing opts

mocha -h|grep -i exclude     --exclude <file>                        a file or glob pattern to ignore (default: )  mocha --exclude **/*-.jest.js 

Additionally, you can also create a test/mocha.opts file and add it there

# test/mocha.opts --exclude **/*-test.jest.js --require ./test/setup.js 

If you want to exclude a particular file type you could do something like this

// test/setup.js require.extensions['.graphql'] = function() {   return null } 

This is useful when processing extensions with a module loader such as webpack that mocha does not understand.