Run Batch File On Start-up

Question

Is there a way to start multiple programs in a batch file on system start-up? In addition to that, in that batch file, I would like to be able to say: Once I execute a program, wait until that program completely loads, and execute the next listed program.

Any help would be appreciated.

Answer 1

I had the same issue in Win7 regarding running a script (.bat) at startup (When the computer boots vs when someone logs in) that would modify the network parameters using netsh. What ended up working for me was the following:

1. Log in with an Administrator account
2. Click on start and type “Task Scheduler” and hit return
3. Click on “Task Scheduler Library”

4. Click on “Create New Task” on the right hand side of the screen and set the parameters as follows:

   a. Set the user account to SYSTEM

   b. Choose "Run with highest privileges"

   c. Choose the OS for Windows7

5. Click on “Triggers” tab and then click on “New…” Choose “At Startup” from the drop down menu, click Enabled and hit OK
6. Click on the “Actions tab” and then click on “New…” If you are running a .bat file use cmd as the program the put /c .bat In the Add arguments field
7. Click on “OK” then on “OK” on the create task panel and it will now be scheduled.
8. Add the .bat script to the place specified in your task event.
9. Enjoy.

Answer 2

To run a batch file at start up: start >> all programs >> right-click startup >> open >> right click batch file >> create shortcut >> drag shortcut to startup folder.

The path to the folder is : [D|C]:\Profiles\{User}\‌​AppData\Roaming\Micro‌​soft\Windows\Start Menu\Programs\Startu‌​p

Answer 3

Go to Run (WINDOWS + R) and Type shell:startup, paste your .bat file there !