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Ruby string search: which is faster split or regex?

Tags:

regex

ruby

This is a two part question. Given you have an array of strings that can be split at a character (e.g. email addresses at '@' or file names at '.') which is the the most performant way of finding the characters before the split character?

my_string.split(char)[0]

or

my_string[/regex/]

The second part of the question is what's how do you write a regex to get everything before the first instance of a character. The regex below finds certain characters before a '.' (because '.' is not in the pattern) but that was my hacky way to get to a solution.

my_string[/[A-Za-z0-9\_-]+/]

thanks!

like image 951
kreek Avatar asked Sep 23 '11 18:09

kreek


2 Answers

The easiest way to answer the first part is to, as always, benchmark it with your real data. For example:

require 'benchmark'
Benchmark.bm do |x|
  x.report { 50000.times { a = '[email protected]'.split('@')[0] } }
  x.report { 50000.times { a = '[email protected]'[/[^@]+/] } }
end

says (on my setup):

      user     system      total        real
  0.130000   0.010000   0.140000 (  0.130946)
  0.090000   0.000000   0.090000 (  0.096260)

So the regex solution looks a little bit faster but the difference is barely noticeable even with 50 000 iterations. OTOH, the regex solution says exactly what you mean ("give me everything before the first @") whereas the split solution gets your desired result in a slightly roundabout way.

The split approach is probably slower because it has to scan the whole string to split it into pieces, then build an array of the pieces, and finally extract the first element of the array and throw the rest away; I don't know if the VM is clever enough to recognize that it doesn't need to build the array so that's just a bit of quick guess work.

As far as your second question is concerned, say what you mean:

my_string[/[^.]+/]

If you want everything before the first period then say "everything until a period" rather than "the first chunk that is made of these characters (which happen to not contain a period)".

like image 75
mu is too short Avatar answered Oct 26 '22 12:10

mu is too short


partition will be quicker than split as it won't continue checking after the first match.

A regular slice with index will be quicker than a regexp slice.

The regexp slice also slows down considerably as the portion of the string before the match becomes larger. It becomes slower than the original split after ~ 10 characters and then becomes a whole lot worse from there on in. If you have a Regexp without a + or * match, I think it fairs a bit better.

require 'benchmark'
n=1000000

def bench n,email
  printf "\n%s %s times\n", email, n
  Benchmark.bm do |x|
      x.report('split    ') do n.times{ email.split('@')[0]  } end
      x.report('partition') do n.times{ email.partition('@').first  } end
      x.report('slice reg') do n.times{ email[/[^@]+/]  } end
      x.report('slice ind') do n.times{ email[0,email.index('@')]  } end
  end
end


bench n, '[email protected]'
bench n, '[email protected]'
bench n, '[email protected]'
bench n, '[email protected]'
bench n, 'some_really_long_long_email_name@rediculously-extra-long-silly-domain.com'
bench n, 'a'*254 + '@' + 'b'*253    # rfc limits
bench n, 'a'*1000 + '@' + 'b'*1000  # for other string processing

Results 1.9.3p484:

[email protected] 1000000 times
       user     system      total        real
split      0.405000   0.000000   0.405000 (  0.410023)
partition  0.375000   0.000000   0.375000 (  0.368021)
slice reg  0.359000   0.000000   0.359000 (  0.357020)
slice ind  0.312000   0.000000   0.312000 (  0.309018)

[email protected] 1000000 times
       user     system      total        real
split      0.421000   0.000000   0.421000 (  0.432025)
partition  0.374000   0.000000   0.374000 (  0.379021)
slice reg  0.421000   0.000000   0.421000 (  0.411024)
slice ind  0.312000   0.000000   0.312000 (  0.315018)

[email protected] 1000000 times
       user     system      total        real
split      0.593000   0.000000   0.593000 (  0.589034)
partition  0.531000   0.000000   0.531000 (  0.529030)
slice reg  0.764000   0.000000   0.764000 (  0.771044)
slice ind  0.484000   0.000000   0.484000 (  0.478027)

[email protected] 1000000 times
       user     system      total        real
split      0.483000   0.000000   0.483000 (  0.481028)
partition  0.390000   0.016000   0.406000 (  0.404023)
slice reg  0.406000   0.000000   0.406000 (  0.411024)
slice ind  0.312000   0.000000   0.312000 (  0.344020)

some_really_long_long_email_name@rediculously-extra-long-silly-domain.com 1000000 times
       user     system      total        real
split      0.639000   0.000000   0.639000 (  0.646037)
partition  0.609000   0.000000   0.609000 (  0.596034)
slice reg  0.764000   0.000000   0.764000 (  0.773044)
slice ind  0.499000   0.000000   0.499000 (  0.491028)

a<254>@b<253> 1000000 times
       user     system      total        real
split      0.952000   0.000000   0.952000 (  0.960055)
partition  0.733000   0.000000   0.733000 (  0.731042)
slice reg  3.432000   0.000000   3.432000 (  3.429196)
slice ind  0.624000   0.000000   0.624000 (  0.625036)

a<1000>@b<1000> 1000000 times
       user     system      total        real
split      1.888000   0.000000   1.888000 (  1.892108)
partition  1.170000   0.016000   1.186000 (  1.188068)
slice reg 12.885000   0.000000  12.885000 ( 12.914739)
slice ind  1.108000   0.000000   1.108000 (  1.097063)

2.1.3p242 holds about the same % differences but is about 10-30% quicker at everything, except for the regexp split where it slows down even more.

like image 21
Matt Avatar answered Oct 26 '22 13:10

Matt