I have a method that looks like this:
def method(:name => nil, :color => nil, shoe_size => nil) SomeOtherObject.some_other_method(THE HASH THAT THOSE KEYWORD ARGUMENTS WOULD MAKE) end
For any given call, I can accept any combination of optional values. I like the named arguments, because I can just look at the method's signature to see what options are available.
What I don't know is if there is a shortcut for what I have described in capital letters in the code sample above.
Back in the olden days, it used to be:
def method(opts) SomeOtherObject.some_other_method(opts) end
Elegant, simple, almost cheating.
Is there a shortcut for those Keyword Arguments or do I have to reconstitute my options hash in the method call?
If you want to accept keyword arguments, in principle you should always use def foo(k: default) or def foo(k:) or def foo(**kwargs) . Note that Ruby 3.0 doesn't behave differently when calling a method which doesn't accept keyword arguments with keyword arguments.
In ruby, arguments inside a method are passed by reference In ruby, we have a different situation, the variable that we have inside the method stores a reference to an object. Thus, if we will change an object inside the method, then it will be changed also outside the method.
In the code you posted, *args simply indicates that the method accepts a variable number of arguments in an array called args . It could have been called anything you want (following the Ruby naming rules, of course).
A keyword argument is a name-value pair that is passed to the function. Here are some of the advantages: If the values passed with positional arguments are wrong, you will get an error or unexpected behavior. Keyword arguments can be passed in any order.
Yes, this is possible, but it's not very elegant.
You'll have to use the parameters
method, which returns an array of the method's parameters and their types (in this case we only have keyword arguments).
def foo(one: 1, two: 2, three: 3) method(__method__).parameters end #=> [[:key, :one], [:key, :two], [:key, :three]]
Knowing that, there's various ways how to use that array to get a hash of all the parameters and their provided values.
def foo(one: 1, two: 2, three: 3) params = method(__method__).parameters.map(&:last) opts = params.map { |p| [p, eval(p.to_s)] }.to_h end #=> {:one=>1, :two=>2, :three=>3}
So your example would look like
def method(name: nil, color: nil, shoe_size: nil) opts = method(__method__).parameters.map(&:last).map { |p| [p, eval(p.to_s)] }.to_h SomeOtherObject.some_other_method(opts) end
Think carefully about using this. It's clever but at the cost of readability, others reading your code won't like it.
You can make it slightly more readable with a helper method.
def params # Returns the parameters of the caller method. caller_method = caller_locations(length=1).first.label method(caller_method).parameters end def method(name: nil, color: nil, shoe_size: nil) opts = params.map { |p| [p, eval(p.to_s)] }.to_h SomeOtherObject.some_other_method(opts) end
Update: Ruby 2.2 introduced Binding#local_variables
which can be used instead of Method#parameters
. Be careful because you have to call local_variables
before defining any additional local variables inside the method.
# Using Method#parameters def foo(one: 1, two: 2, three: 3) params = method(__method__).parameters.map(&:last) opts = params.map { |p| [p, eval(p.to_s)] }.to_h end #=> {:one=>1, :two=>2, :three=>3} # Using Binding#local_variables (Ruby 2.2+) def bar(one: 1, two: 2, three: 3) binding.local_variables.params.map { |p| [p, binding.local_variable_get(p)] }.to_h end #=> {:one=>1, :two=>2, :three=>3}
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