Rounded <input type='color'>

Question

$("#colour").change(function(event) {
    console.log($(this).val());
});

input[type=color] {
    width: 100px;
    height: 100px; 
    border-radius: 50%;
    overflow: hidden;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type='color' value='#fefefe' class='bar' id='colour'>

Even though I made the <input type='color'> rounded, when I input a value (at least on safari) it changes the circle to a square instead. How can I do this? thanks.

Answer 1

My idea:

1. create one inline-block <span>
2. set input[type=color] to not visible.
3. bind click event of <span> to trigger <input>.click().

Because <input> is not friendly for shape customization.

$("#colour").change(function(event) {
    console.log($(this).val());
    $("#color_front").css('background-color',$(this).val());
});

$("#color_front").click(function(event) {
    $("#colour").click();
});

input[type=color] {
    display: none;
}
span {
  border-radius: 50%;
  width: 100px;
  height: 100px; 
  background-color:red;
  display:inline-block;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<span id="color_front"></span>
<input type='color' value='#fefefe' class='bar' id='colour'>