Round up to Second Decimal Place in Python

Question

How can I round up a number to the second decimal place in python? For example:

0.022499999999999999 

Should round up to 0.03

0.1111111111111000 

Should round up to 0.12

If there is any value in the third decimal place, I want it to always round up leaving me 2 values behind the decimal point.

Answer 1

Python includes the round() function which lets you specify the number of digits you want. From the documentation:

round(x[, n])

Return the floating point value x rounded to n digits after the decimal point. If n is omitted, it defaults to zero. The result is a floating point number. Values are rounded to the closest multiple of 10 to the power minus n; if two multiples are equally close, rounding is done away from 0 (so. for example, round(0.5) is 1.0 and round(-0.5) is -1.0).

So you would want to use round(x, 2) to do normal rounding. To ensure that the number is always rounded up you would need to use the ceil(x) function. Similarly, to round down use floor(x).

Answer 2

from math import ceil  num = 0.1111111111000 num = ceil(num * 100) / 100.0 

See:
math.ceil documentation
round documentation - You'll probably want to check this out anyway for future reference