Round off floating point values in dict

Question

I am struggling to round off floating values in dictionary. To generate the dictionary I have used:

[{i: x.count(i)/float(len(x)) for i in x} for x in l]

My dictionary is:

P = [{'A': 0.700000000, 'B': 0.255555555}, {'B': 0.55555555, 'C': 0.55555555}, {'A': 0.255555555, 'B': 0.210000000, 'C': 0.2400000000}]

I need:

P = [{'A': 0.70, 'B': 0.25}, {'B': 0.55, 'C': 0.55}, {'A': 0.25, 'B': 0.21, 'C': 0.24}]

Answer 1

This is a fairly simple way to do it. However, .7000 will become just .7

Rounding

for dict_value in P:
        for k, v in dict_value.items():
            dict_value[k] = round(v, 2)

[{'A': 0.7, 'B': 0.26}, {'C': 0.56, 'B': 0.56}, {'A': 0.26, 'C': 0.24, 'B': 0.21}]

Truncating

for dict_value in P:
    for k, v in dict_value.items():
        dict_value[k] = float(str(v)[:4])
[{'A': 0.7, 'B': 0.25}, {'C': 0.55, 'B': 0.55}, {'A': 0.25, 'C': 0.24, 'B': 0.21}]

The conversion to string chops off the extra 0's in 0.700000 and that is why it still shows as 0.7 instead of 0.70.