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If the digit is 0, 1, 2, 3, or 4, do not change the rounding digit. All digits that are on the righthand side of the requested rounding digit become 0. If the digit is 5, 6, 7, 8, or 9, the rounding digit rounds up by one number. All digits that are on the righthand side of the requested rounding digit will become 0.
Rounding towards zero is the simplest rounding mode computationally. All digits beyond the number required are dropped. Rounding towards zero results in a number whose magnitude is always less than or equal to the more precise original value.
A round number is an integer that ends with one or more "0"s (zero-digit) in a given base. So, 590 is rounder than 592, but 590 is less round than 600. In both technical and informal language, a round number is often interpreted to stand for a value or values near to the nominal value expressed.
Python has a built-in round() function that takes two numeric arguments, n and ndigits , and returns the number n rounded to ndigits . The ndigits argument defaults to zero, so leaving it out results in a number rounded to an integer.
is there a predefined format-function that rounds a number to the first 3 digits? (The start should be a numbers != 0)
-0.02528498 to -0.0253
1.857403 to 1.86
2060943 to 2060000
0.00006513832 to 0.0000651
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