I'm trying to do an echo of a variable containing 1400000.
so there is written: echo round(1400000);
this gives 1,4E+6 instead of the full number.
Anybody an idea on how to display it fully?
It seems that round was the problem.
I changed it with number_format()
and this does the job just fine.
Thanks Aron and Paul for the answers.
Related to your question, I also came across this comment on the PHP website.
PHP switches from the standard decimal notation to exponential notation for certain "special" floats. You can see a partial list of such "special" values with this:
for( $tmp = 0, $i = 0; $i < 100; $i++ )
{
$tmp += 100000;
echo round($tmp),"\n";
}
So, if you add two floats, end up with a "special" value, e.g. 1.2E+6, then put that value unmodified into an update query to store the value in a decimal column, say, you will likely get a failed transaction, since the database will see "1.2E+6" as varchar data, not decimal. Likewise, you will likely get an XSD validation error if you put the value into xml.
I have to be honest: this is one of the strangest things I have seen in any language in over 20 years of coding, and it is a colossal pain to work around.
It seems there has not been a "real" fix yet, but judging from the comments in the bug report Paul Dixon referered to earlier, his solution seems to work.
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