I want to know how to work out the new co-ordinates for a point when rotated by an angle relative to another point.
I have a block arrow and want to rotate it by an angle theta relative to a point in the middle of the base of the arrow.
This is required to allow me to draw a polygon between 2 onscreen controls. I can't use and rotate an image.
From what I have considered so far what complicates the matter further is that the origin of a screen is in the top left hand corner.
If you rotate point (px, py)
around point (ox, oy)
by angle theta
you'll get:
p'x = cos(theta) * (px-ox) - sin(theta) * (py-oy) + ox p'y = sin(theta) * (px-ox) + cos(theta) * (py-oy) + oy
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