How can I rotate a 2D rectangular array of integers that has odd number of rows by 45 degrees?
So something like
int[] myArray = new int[,]
{
{1, 0 ,1},
{0, 1 ,0},
{0, 0 ,0},
}
into
int[] rotatedArray = new int[,]
{
{0, 1 ,0},
{0, 1 ,1},
{0, 0 ,0},
}
for any dimension (3x3, 5x5, 7x7, etc.).
5x5
0 0 0 0 0
2 0 0 0 0
1 1 1 1 1
0 0 0 0 0
0 0 0 0 0
into
1 2 0 0 0
0 1 0 0 0
0 0 1 0 0
0 0 0 1 0
0 0 0 0 1
5x5
0 0 0 3 0
0 0 0 3 0
0 0 0 3 0
0 0 0 3 0
0 0 0 3 0
into
0 0 0 0 0
0 0 0 0 3
0 0 0 3 0
0 0 3 3 0
0 3 0 0 0
This is a code written by me and a friend that solves this:
public static class ArrayExtensions
{
public static Point RoundIndexToPoint(int index, int radius)
{
if (radius == 0)
return new Point(0, 0);
Point result = new Point(-radius, -radius);
while (index < 0) index += radius * 8;
index = index % (radius * 8);
int edgeLen = radius * 2;
if (index < edgeLen)
{
result.X += index;
}
else if ((index -= edgeLen) < edgeLen)
{
result.X = radius;
result.Y += index;
}
else if ((index -= edgeLen) < edgeLen)
{
result.X = radius - index;
result.Y = radius;
}
else if ((index -= edgeLen) < edgeLen)
{
result.Y = radius - index;
}
return result;
}
public static T[,] Rotate45<T>(this T[,] array)
{
int dim = Math.Max(array.GetLength(0), array.GetLength(0));
T[,] result = new T[dim, dim];
Point center = new Point((result.GetLength(0) - 1) / 2, (result.GetLength(1) - 1) / 2);
Point center2 = new Point((array.GetLength(0) - 1) / 2, (array.GetLength(1) - 1) / 2);
for (int r = 0; r <= (dim - 1) / 2; r++)
{
for (int i = 0; i <= r * 8; i++)
{
Point source = RoundIndexToPoint(i, r);
Point target = RoundIndexToPoint(i + r, r);
if (!(center2.X + source.X < 0 || center2.Y + source.Y < 0 || center2.X + source.X >= array.GetLength(0) || center2.Y + source.Y >= array.GetLength(1)))
result[center.X + target.X, center.Y + target.Y] = array[center2.X + source.X, center2.Y + source.Y];
}
}
return result;
}
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With