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Room - Select query with IN condition?

Is it possible to use SQLite's IN condition with Room?

I'm trying to select a list of items from my database where the value of a certain column (in this case a TEXT column) matches any one of a set of filter values. That's pretty easily done in SQL and SQLite, by my knowledge, just by adding an IN condition to your SELECT statement (see here). However, I can't seem to make it work with Room.

I keep getting this error:

Error:(70, 25) error: no viable alternative at input 'SELECT * FROM Table WHERE column IN :filterValues'

(where the input to the DAO @Query-annotated method is called filterValues)

I have tried three different methods now:

  1. Passing the argument as a List<String>
  2. Passing the argument as a String[]
  3. And lastly passing the argument as simply a String, but formatted as (value_1, value_2, ..., value_n)

The last one in particular should work easily, as it will (or at least, it should) directly translate to SELECT * FROM Table WHERE column IN (value_1, value_2, ..., value_n), which is the exact way you would manually write out the SELECT if you were just accessing the database directly.

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VerumCH Avatar asked Jan 23 '18 16:01

VerumCH


3 Answers

So as I was preparing to submit this, I double-checked a bunch of the stuff I had looked up previously and found the thing I had somehow missed and would have saved this question from being necessary.

As it turns out, both of these options:

  1. Passing the argument as a List<String>
  2. Passing the argument as a String[]

are viable (and you can replace String with any type the database can represent, such as char or int), you simply need to change the syntax in the @Query annotation from this:

@Query("SELECT * FROM Table WHERE column IN :filterValues")

to this:

@Query("SELECT * FROM Table WHERE column IN (:filterValues)")

Easy as pie, right?

Note that the third method above (passing the argument as simply a String, but formatted as (value_1, value_2, ..., value_n)) does not appear to be supported by Room, but that's probably not a bad thing, since that's the hard way.

Since I already had the whole thing typed out, I figured I would leave the question up in case other people are have as much difficulty finding this solution as I did and stumble upon this question.

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VerumCH Avatar answered Nov 10 '22 11:11

VerumCH


Hi you can use this query:

 @Query("SELECT * FROM user WHERE uid IN(:userIds)")
 public abstract List findByIds(int[] userIds);

or

 @Query("SELECT * FROM user WHERE uid IN(:userIds)")
 public abstract List findByIds(List<Integer> userIds);
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Ahmad Aghazadeh Avatar answered Nov 10 '22 11:11

Ahmad Aghazadeh


Similarly to above answers in Kotlin you can use vararg instead of array or list:

@Query("SELECT * FROM user WHERE uid IN (:userIds)")
fun getUsers(vararg userIds: Int): List<User>?

and use it like repository.getUsers(1, 2, 3).

If needed, to convert vararg to list see https://proandroiddev.com/kotlins-vararg-and-spread-operator-4200c07d65e1 (use *: format(output, *params)).

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CoolMind Avatar answered Nov 10 '22 13:11

CoolMind