Reversing a string in python based on block size in python

Question

Im trying to reverse a string based on the block size given

for example

"the price of food is 12 dollars" and im given a block size of 4

i want the end result to be:

food of price the dollars 12 is

im not sure how to input this into python any help would be appreciated i need this to work for any block size

Answer 1

def chunks(seq, n):
    return [seq[i:i+n] for i in range(0, len(seq), n)]

s = "the price of food is 12 dollars"
' '.join(' '.join(reversed(chunk)) for chunk in chunks(s.split(), 4))

Related: How do you split a list into evenly sized chunks in Python?

Answer 2

Using itertools grouper recipe:

>>> from itertools import izip_longest
>>> def grouper(n, iterable, fillvalue=None):
        "Collect data into fixed-length chunks or blocks"
        # grouper(3, 'ABCDEFG', 'x') --> ABC DEF Gxx
        args = [iter(iterable)] * n
        return izip_longest(fillvalue=fillvalue, *args)

>>> text = "the price of food is 12 dollars"
>>> ' '.join(word for g in grouper(4, text.split()) 
                  for word in reversed(g) if word)
'food of price the dollars 12 is'