I have a table RDCAlerts
with the following data in a column of type XML
called AliasesValue
:
<aliases>
<alias>
<aliasType>AKA</aliasType>
<aliasName>Pramod Singh</aliasName>
</alias>
<alias>
<aliasType>AKA</aliasType>
<aliasName>Bijoy Bora</aliasName>
</alias>
</aliases>
I would like to create a query that returns two rows - one for each alias and I've tried the following query:
SELECT
AliasesValue.query('data(/aliases/alias/aliasType)'),
AliasesValue.query('data(/aliases/alias/aliasName)'),
FROM [RdcAlerts]
but it returns just one row like this:
AKA AKA | Pramod Singh Bijoy Bora
Look at the .nodes() method in Books Online:
DECLARE @r TABLE (AliasesValue XML)
INSERT INTO @r
SELECT '<aliases> <alias> <aliasType>AKA</aliasType> <aliasName>Pramod Singh</aliasName> </alias> <alias> <aliasType>AKA</aliasType> <aliasName>Bijoy Bora</aliasName> </alias> </aliases> '
SELECT c.query('data(aliasType)'), c.query('data(aliasName)')
FROM @r r CROSS APPLY AliasesValue.nodes('aliases/alias') x(c)
You need to use the CROSS APPLY
statement along with the .nodes()
function to get multiple rows returned.
select
a.alias.value('(aliasType/text())[1]', 'varchar(20)') as 'aliasType',
a.alias.value('(aliasName/text())[1]', 'varchar(20)') as 'aliasName'
from
RDCAlerts r
cross apply r.AliasesValue.nodes('/aliases/alias') a(alias)
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