Return Object from map() function not Array

Question

Sorry if the title is misleading I'm not sure how to accurately describe what I am looking for.

I have an array result which I want to turn into multiple objects where each objects property is the field Name Test I need to keep my result.map method as I use it to merge result with data

  result = [{
      "Name Test": "Yellow",
      Count: 124,

    },
    {
      "Name Test": "Black",
      Count: 124,
    },
    {
      "Name Test": "Blue",
      Count: 124,
    }
  ];

  data = [{
      "Name Test": "Yellow",
      pop: 1
    },
    {
      "Name Test": "Black",
      pop: 1
    },
    {
      "Name Test": "Blue",
      pop: 1
    }
  ];


result = result.map((obj1, index) => {
    const obj2 = data[index];
    return {
        [obj1["Name Test"].toUpperCase()]: {
            Count: obj1.Count,
            pop: obj2.pop,
        }
    };
});
console.log(JSON.stringify(result))

This code returns an array of objects which is not what I want as I need to be able to use result["YELLOW"] later in my code. I therefore need the result to be in this format, with no arrays.

{  
   "YELLOW":{  
      "Count":124,
      "pop":1
   },
   "BLACK":{  
      "Count":124,
      "pop":1
   },
   "BLUE":{  
      "Count":124,
      "pop":1
   }
}

I hope this makes sense and I feel I am very close to what I want and just am missing something small, but every way I have tried to make this work turns into a syntax error.

Answer 1

map() will always return an array.

• You should use reduce() and set accumulator to empty object {}

• Use the destructuring and spread syntax to isolate Name Test and other properties.

• Set the property of accumulator whose key is "Name Test" property of each object and its value is rest of the object.

const arr = [{ "Name Test": "Yellow", Count: 124, pop: 1 }, { "Name Test": "Black", Count: 124, pop: 1 }, { "Name Test": "Blue", Count: 124, pop: 1 } ];

const res = arr.reduce((ac,{["Name Test"]:x,...rest}) => (ac[x] = rest,ac),{})

console.log(res)