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Is there a way to get PHP to return an AJAX error code if the PHP script fails somewhere? I was following a tutorial and typed this in to my PHP:
$return['error'] = true; $return['msg'] = "Could not connect to DB";
And all was well, until I realised it was JSON data. Is there a way to return errors using standard $_POST and returned HTML data (as in, trigger jQuery's AJAX error: event?
864
The best way to bubble that error from the server side (using php) to the client side is to send a header through the Ajax request somewhere in the 400's (which is always associated with errors). Once the Ajax request receives this it will trigger your error function.
You can store your promise, you can pass it around, you can use it as an argument in function calls and you can return it from functions, but when you finally want to use your data that is returned by the AJAX call, you have to do it like this: promise. success(function (data) { alert(data); });
You can't return "true" until the ajax requests has not finished because it's asynchron as you mentioned. So the function is leaved before the ajax request has finished.
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I don't know about jQuery, but if it distinguishes between successful and unsuccessful (HTTP 200 OK vs. HTTP != 200) Ajax requests, you might want your PHP script respond with an HTTP code not equal to 200:
if ($everything_is_ok)
{
header('Content-Type: application/json');
print json_encode($result);
}
else
{
header('HTTP/1.1 500 Internal Server Booboo');
header('Content-Type: application/json; charset=UTF-8');
die(json_encode(array('message' => 'ERROR', 'code' => 1337)));
}
$return = array();
$return['msg'] = "Could not connect to DB";
if(isset($_SERVER['HTTP_X_REQUESTED_WITH']) && $_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest')
{
header('Cache-Control: no-cache, must-revalidate');
header('Expires: Mon, 26 Jul 1997 05:00:00 GMT');
header('Content-type: application/json');
die(json_encode($return));
}
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