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Retain Checkbox values in Yii gridview pagination

I have a gridview which contains a checkbox column and also uses pagination. When I check some checkboxes in the first page and navigate to the second page and check another one in the second page, the options I checked in the first page is not retained there. Is it posssible to retain the checkbox values during pagination?

Code for Gridview is

$widget = $this->widget('zii.widgets.grid.CGridView', array(
    'dataProvider'     => $model->search(),
    'cssFile'          => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',
    //'filter' => $model,
    'ajaxUpdate'       => true,
    'enablePagination' => true,
    'columns'          => array(
        array(
            'name'   => 'id',
            'header' => '#',
            'value'  => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
        ),
        array(
            'class'          => 'CCheckBoxColumn',
            'selectableRows' => '2',
            'header' => 'Selected',
        ),
        array(
            'name'   => 'fb_user_id',
            'header' => 'FaceBook Id',
            'value'  => 'CHtml::encode($data->fb_user_id)',
        ),
        array(
            'name'   => 'first_name',
            'header' => 'Name',
            'value'  => 'CHtml::encode($data->first_name)',
        ),
        array(
            'name'   => 'email_id',
            'header' => 'Email',
            'value'  => 'CHtml::encode($data->email_id)',
        ),
        array(
            'name'   => 'demo',
            'type'   => 'raw',
            'header' => "Select",
            'value'  => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
        ),
    ),
));

Edit:

Extension for remembering the selected options in gridview,check this link Selgridview

Thanks to bool.dev

like image 233
Gopesh Avatar asked Apr 11 '12 04:04

Gopesh


2 Answers

You could use sessions/cookies to store the checked values. I'm not very sure how to make cookies work, so i'll tell you how to do it with sessions. Specifically the user session that yii creates.

Now to use sessions we need to pass the checked (and unchecked) ids to the controller, therefore we'll modify the data being sent to the controller on every ajax update(i.e between paginations), to do this we exploit the beforeAjaxUpdate option of CGridView.

I'm also using CCheckBoxColumn instead of the following in your code(of course you can modify the solution to suit your own needs):

array(
     'name' => 'demo',
     'type'=>'raw',
     'header' => "Select",
     'value' => 'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
),

GridView Changes:

<?php $this->widget('zii.widgets.grid.CGridView', array(
    // added id of grid-view for use with $.fn.yiiGridView.getChecked(containerID,columnID)
    'id'=>'first-grid',

    'dataProvider'=>$model->search(),
    'cssFile' => Yii::app()->baseUrl . '/media/js/admin/css/admingridview.css',

    // added this piece of code
    'beforeAjaxUpdate'=>'function(id,options){options.data={checkedIds:$.fn.yiiGridView.getChecked("first-grid","someChecks").toString(),
        uncheckedIds:getUncheckeds()};
        return true;}',

    'ajaxUpdate'=>true,
    'enablePagination' => true,
    'columns' => array(
            array(
                 'name' => 'id',
                 'header' => '#',
                 'value' => '$this->grid->dataProvider->pagination->currentPage * $this->grid->dataProvider->pagination->pageSize + ($row+1)',
            ),
            array(
                 'name' => 'fb_user_id',
                 'header' => 'FaceBook Id',
                 'value' => 'CHtml::encode($data->fb_user_id)',
            ),
            array(
                 'name' => 'first_name',
                 'header' => 'Name',
                 'value' => 'CHtml::encode($data->first_name)',
            ),
            array(
                 'name' => 'email_id',
                 'header' => 'Email',
                 'value' => 'CHtml::encode($data->email_id)',
            ),

            /* replaced the following with CCheckBoxColumn
              array(
                 'name' => 'demo',
                 'type'=>'raw',
                 'header' => "Select",
                 'value' =>'CHtml::checkBox("email[]","",array("class"=>"check","value"=>$data->email_id))',
              ),
            */

            array(
                 'class' => 'CCheckBoxColumn',
                 'selectableRows' => '2',
                 'header'=>'Selected',
                 'id'=>'someChecks', // need this id for use with $.fn.yiiGridView.getChecked(containerID,columnID)
                 'checked'=>'Yii::app()->user->getState($data->email_id)', // we are using the user session variable to store the checked row values, also considering here that email_ids are unique for your app, it would be best to use any field that is unique in the table
            ),
    ),
));
?>

Pay special attention to the code for beforeAjaxUpdate and CCheckBoxColumn, in beforeAjaxUpdate we are passing checkedIds as a csv string of all the ids(in this case email_ids) that have been checked and uncheckedIds as a csv string of all the unchecked ids, we get the unchecked boxes by calling a function getUncheckeds(), which follows shortly. Please take note here, that when i was testing i had used an integer id field (of my table) as the unique field, and not an email field.

The getUncheckeds() function can be registered like this anywhere in the view file for gridview:

Yii::app()->clientScript->registerScript('getUnchecked', "
       function getUncheckeds(){
            var unch = [];
            /*corrected typo: $('[name^=someChec]') => $('[name^=someChecks]') */
            $('[name^=someChecks]').not(':checked,[name$=all]').each(function(){unch.push($(this).val());});
            return unch.toString();
       }
       "
);

In the above function pay attention to the selectors and each and push function.

With that done, we need to modify the controller/action for this view.

public function actionShowGrid(){
     // some code already existing
     // additional code follows
     if(isset($_GET['checkedIds'])){
          $chkArray=explode(",", $_GET['checkedIds']);
          foreach ($chkArray as $arow){
               Yii::app()->user->setState($arow,1);
          }
     }
     if(isset($_GET['uncheckedIds'])){
          $unchkArray=explode(",", $_GET['uncheckedIds']);
          foreach ($unchkArray as $arownon){
               Yii::app()->user->setState($arownon,0);
          }
     }
     // rest of the code namely render()
}

That's it, it should work now.

like image 143
bool.dev Avatar answered Oct 05 '22 22:10

bool.dev


For developing that scheme you would need to know working of what happens when you navigate.

When ever you navigate to a pagination page ajax calls are made and new data is received and it is fetched from CActive Record or what ever the data source. New data is in accordance of database records or source records. when you come back to previous page again Ajax call is made and content is updated so same comes as it is in database.

what i feel is you should save data of checked items temporary and make it permanent if action is made.

You can do something like this

<script type="text/javascript">
$("input:checkbox").click(function () {
    var thisCheck = $(this);
    if (thisCheck.is (':checked')){
        // do what you want here, the way to access the text is using the
        // $(this) selector. The following code would output pop up message with
        // the selected checkbox text
        $(this).val());
    }
});
</script>

you can save temporary storage somewhere

like image 33
Afnan Bashir Avatar answered Oct 05 '22 21:10

Afnan Bashir