I'm playing around with node streams and child processes. So I want to emulate next shell command with pipes:
ps au | grep ssh
So I wrote next code:
var spawn = require('child_process').spawn;
var ps = spawn('ps', ['au']);
var grep = spawn('grep', ['ssh']);
ps.stdout.pipe(grep.stdin);
grep.stdout.on('data', function(data) { console.log(data) });
Then I run it, but nothing happens. What did I do wrong?
P.S. - I know about:
require('child_process')
.exec('ps au | grep ssh', function(err, stdout, stderr) {
...
}).
I'm just playing around with Node.js, and I want to understand what's wrong with this example.
Update 1:
It appeared that with grep bash
program works as expected, but with grep ssh
there is no result. Although ps au | grep ssh
gives me this result:
vagrant 11681 0.0 0.1 10464 916 pts/0 S+ 07:54 0:00 grep --color=auto ssh.
When you call ps
it will list all currently running processes matching the passed options. Which might look for ps au
something like this:
tniese 3251 0,0 0,0 2479028 3004 s000 S+ 4:06am 0:00.03 -bash
root 4453 0,0 0,0 2452408 876 s004 R+ 4:06pm 0:00.00 ps au
When you call ps au | grep ssh
in the shell grep
will filter that result to only show the lines containing ssh
.
If the grep
is launched by the shell before ps
creates its listing then the output before the filtering would be:
tniese 3251 0,0 0,0 2479028 3004 s000 S+ 4:06am 0:00.03 -bash
root 4453 0,0 0,0 2452408 876 s004 R+ 4:06pm 0:00.00 ps au
tniese 4478 0,0 0,0 2441988 596 s000 R+ 4:06pm 0:00.00 grep ssh
The grep
process will match its own entry as it contains the passed parameters, so the filtered result would be:
tniese 4478 0,0 0,0 2441988 596 s000 R+ 4:06pm 0:00.00 grep ssh
Lets look what is happening with your code:
var spawn = require('child_process').spawn;
var ps = spawn('ps', ['au']);
var grep = spawn('grep', ['ssh']);
ps.stdout.pipe(grep.stdin);
With spawn you tell the OS to start the process ps
, ps
does not need to wait to run until the output could be piped to anyplace but could start before that, it might only be forced to wait when it tries to write to the its output stream. Then your spawn grep
, but at the time grep
is launched ps
might already created the process listing internally and cause of that it does not contain the grep
process. The output of ps
is then passed to grep. But as this output is missing grep ssh
it won't show that line.
Wether grep
will appear in your listing or not is highly OS dependent. Generally you should assume that it is random if it is listed or not. Or you would need to wait until ps
exits and launch grep
after that.
You need to always keep in mind that current OS have preemptive multitasking and that the scheduler might pause node right after spawn('ps', ['au']);
and continue the process right after ps
created/requested the listing.
I hope this explanation is a bit clearer then my comment.
I've spawned grep before ps and now it works well. I think it must be a timing issue. Try this.
var spawn = require('child_process').spawn;
var grep = spawn('grep', ['ssh']);
var ps = spawn('ps', ['au']);
ps.stdout.pipe(grep.stdin);
grep.stdout.on('data', function(data) {
console.log(data.toString("utf8"));
});
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