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Resolve absolute path from relative path and/or file name

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How do I find the absolute path of a file?

The getAbsolutePath() method is a part of File class. This function returns the absolute pathname of the given file object. If the pathname of the file object is absolute then it simply returns the path of the current file object.

What is the difference between absolute and relative path name of a file?

An absolute path is defined as specifying the location of a file or directory from the root directory(/). In other words,we can say that an absolute path is a complete path from start of actual file system from / directory. Relative path is defined as the path related to the present working directly(pwd).


In batch files, as in standard C programs, argument 0 contains the path to the currently executing script. You can use %~dp0 to get only the path portion of the 0th argument (which is the current script) - this path is always a fully qualified path.

You can also get the fully qualified path of your first argument by using %~f1, but this gives a path according to the current working directory, which is obviously not what you want.

Personally, I often use the %~dp0%~1 idiom in my batch file, which interpret the first argument relative to the path of the executing batch. It does have a shortcoming though: it miserably fails if the first argument is fully-qualified.

If you need to support both relative and absolute paths, you can make use of Frédéric Ménez's solution: temporarily change the current working directory.

Here's an example that'll demonstrate each of these techniques:

@echo off
echo %%~dp0 is "%~dp0"
echo %%0 is "%0"
echo %%~dpnx0 is "%~dpnx0"
echo %%~f1 is "%~f1"
echo %%~dp0%%~1 is "%~dp0%~1"

rem Temporarily change the current working directory, to retrieve a full path 
rem   to the first parameter
pushd .
cd %~dp0
echo batch-relative %%~f1 is "%~f1"
popd

If you save this as c:\temp\example.bat and the run it from c:\Users\Public as

c:\Users\Public>\temp\example.bat ..\windows

...you'll observe the following output:

%~dp0 is "C:\temp\"
%0 is "\temp\example.bat"
%~dpnx0 is "C:\temp\example.bat"
%~f1 is "C:\Users\windows"
%~dp0%~1 is "C:\temp\..\windows"
batch-relative %~f1 is "C:\Windows"

the documentation for the set of modifiers allowed on a batch argument can be found here: https://docs.microsoft.com/en-us/windows-server/administration/windows-commands/call


I came across a similar need this morning: how to convert a relative path into an absolute path inside a Windows command script.

The following did the trick:

@echo off

set REL_PATH=..\..\
set ABS_PATH=

rem // Save current directory and change to target directory
pushd %REL_PATH%

rem // Save value of CD variable (current directory)
set ABS_PATH=%CD%

rem // Restore original directory
popd

echo Relative path: %REL_PATH%
echo Maps to path: %ABS_PATH%

Most of these answers seem crazy over complicated and super buggy, here's mine -- it works on any environment variable, no %CD% or PUSHD/POPD, or for /f nonsense -- just plain old batch functions. -- The directory & file don't even have to exist.

CALL :NORMALIZEPATH "..\..\..\foo\bar.txt"
SET BLAH=%RETVAL%

ECHO "%BLAH%"

:: ========== FUNCTIONS ==========
EXIT /B

:NORMALIZEPATH
  SET RETVAL=%~f1
  EXIT /B

Without having to have another batch file to pass arguments to (and use the argument operators), you can use FOR /F:

FOR /F %%i IN ("..\relativePath") DO echo absolute path: %%~fi

where the i in %%~fi is the variable defined at /F %%i. eg. if you changed that to /F %%a then the last part would be %%~fa.

To do the same thing right at the command prompt (and not in a batch file) replace %% with %...


This is to help fill in the gaps in Adrien Plisson's answer (which should be upvoted as soon as he edits it ;-):

you can also get the fully qualified path of your first argument by using %~f1, but this gives a path according to the current path, which is obviously not what you want.

unfortunately, i don't know how to mix the 2 together...

One can handle %0 and %1 likewise:

  • %~dpnx0 for fully qualified drive+path+name+extension of the batchfile itself,
    %~f0 also suffices;
  • %~dpnx1 for fully qualified drive+path+name+extension of its first argument [if that's a filename at all],
    %~f1 also suffices;

%~f1 will work independent of how you did specify your first argument: with relative paths or with absolute paths (if you don't specify the file's extension when naming %1, it will not be added, even if you use %~dpnx1 -- however.

But how on earth would you name a file on a different drive anyway if you wouldn't give that full path info on the commandline in the first place?

However, %~p0, %~n0, %~nx0 and %~x0 may come in handy, should you be interested in path (without driveletter), filename (without extension), full filename with extension or filename's extension only. But note, while %~p1 and %~n1 will work to find out the path or name of the first argument, %~nx1 and %~x1 will not add+show the extension, unless you used it on the commandline already.


You can also use batch functions for this:

@echo off
setlocal 

goto MAIN
::-----------------------------------------------
:: "%~f2" get abs path of %~2. 
::"%~fs2" get abs path with short names of %~2.
:setAbsPath
  setlocal
  set __absPath=%~f2
  endlocal && set %1=%__absPath%
  goto :eof
::-----------------------------------------------

:MAIN
call :setAbsPath ABS_PATH ..\
echo %ABS_PATH%

endlocal