I am using python 3 and latest version of openCV. I am trying to resize an image using the resize function provided but after resizing the image is very distorted. Code :
import cv2 file = "/home/tanmay/Desktop/test_image.png" img = cv2.imread(file , 0) print(img.shape) cv2.imshow('img' , img) k = cv2.waitKey(0) if k == 27: cv2.destroyWindow('img') resize_img = cv2.resize(img , (28 , 28)) cv2.imshow('img' , resize_img) x = cv2.waitKey(0) if x == 27: cv2.destroyWindow('img')
The original image is 480 x 640 (RGB therefore i passed the 0 to get it to grayscale)
Is there any way i could resize it and avoid the distortion using OpenCV or any other library perhaps? I intend to make a handwritten digit recogniser and i have trained my neural network using the MNIST data therefore i need the image to be 28x28.
To resize an image in Python, you can use cv2. resize() function of OpenCV library cv2. Resizing, by default, does only change the width and height of the image. The aspect ratio can be preserved or not, based on the requirement.
You may try below. The function will keep the aspect rate of the original image.
def image_resize(image, width = None, height = None, inter = cv2.INTER_AREA): # initialize the dimensions of the image to be resized and # grab the image size dim = None (h, w) = image.shape[:2] # if both the width and height are None, then return the # original image if width is None and height is None: return image # check to see if the width is None if width is None: # calculate the ratio of the height and construct the # dimensions r = height / float(h) dim = (int(w * r), height) # otherwise, the height is None else: # calculate the ratio of the width and construct the # dimensions r = width / float(w) dim = (width, int(h * r)) # resize the image resized = cv2.resize(image, dim, interpolation = inter) # return the resized image return resized
Here is an example usage.
image = image_resize(image, height = 800)
Hope this helps.
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