I need some help with the concept of only loading modules when they are needed using requireJS
this is my main.js
require(['jquery', 'path/somemodule'],
function($, somemodule) {
$(document).ready(function() {
somemodule.init()
})
})
and in the somemodule.js
define(['jquery', 'path/someothermodule'], function ($, someothermodule) {
"use strict";
var somemodule;
somemodule = {
init: function () {
someothermodule.init()
}
}
return somemodule;
)}
right now somemodule.js and someothermodule.js is loaded on all pages. How do I only load it when it's needed?
When you require a module2 from module1 using the standard define() syntax module1 will not load/run until module2 has been fully loaded. That looks like this:
// inside module1
define(['module2'], function(mod2) {
// we don't get here until AFTER module2 has already been loaded
});
An alternative to lazy-load module2 looks like this:
// inside module1
define([], function() {
require(['module2'], function(mod2) {
// we don't get here until AFTER module2 has already been loaded
});
// but we DO get here without having loaded module2
});
Now you have to program somewhat carefully to make sure you don't run into any issues with asynchronicity.
In your case you can modify your main.js file
require(['jquery'],
function($) {
// jquery is loaded, but somemodule has not
if(thisPageNeedsSomeModule) {
require(['path/somemodule'],
function(somemodule) {
// now somemodule has loaded
$(document).ready(function() {
somemodule.init()
})
});
}
})
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