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replacing values in a column with another column R

I have two tables in different dimensions, now I want to replace value datA$swl1 with values in datB$swl2 according to userids.

datA

 id swl1
 1   0.8
 2   0.7
 3   0.4
 4   0.7
 5   0.0

datB

id   swl2
 1   0.8
 3   0.6
 5   0.7

output

datA (here swl1 is replaced by the new values in swl2, but not all the ids have a new values, for those that haven't, the original values are retained)

 id swl1
 1   0.8
 2   0.7
 3   0.6
 4   0.7
 5   0.7

how to do this?

like image 435
Lucia Avatar asked Aug 27 '15 02:08

Lucia


3 Answers

You can use merge to match by id, then replace in column swl1 those items from datB which exist:

datC <- merge(datA, datB, all.x=TRUE)
datC
##   id swl1 swl2
## 1  1  0.8  0.8
## 2  2  0.7   NA
## 3  3  0.4  0.6
## 4  4  0.7   NA
## 5  5  0.0  0.7

This matches up the rows. Now to replace those values in column swl1 with the non-NA values from column swl2:

datC$swl1 <- ifelse(is.na(datC$swl2), datC$swl1, datC$swl2)
datC$swl2 <- NULL
datC
##   id swl1
## 1  1  0.8
## 2  2  0.7
## 3  3  0.6
## 4  4  0.7
## 5  5  0.7
like image 99
Matthew Lundberg Avatar answered Sep 22 '22 01:09

Matthew Lundberg


You can obtain this result with one line of code:

datA$swl1[datA$id %in% datB$id] <- datB$swl2
#> datA
#  id swl1
#1  1  0.8
#2  2  0.7
#3  3  0.6
#4  4  0.7
#5  5  0.7

With the %in% operator we select the entries of the column datA$swl1 that belong to rows with the same id as those listed in datB. These values in the column of datA$swl1 are then replaced with the entries of the swl2 column of datB.

like image 39
RHertel Avatar answered Sep 18 '22 01:09

RHertel


IIUC, using data.table v1.9.5:

require(data.table)
setDT(datA)[datB, swl1 := swl2, on = "id"]

datA is updated by reference.

like image 42
Arun Avatar answered Sep 22 '22 01:09

Arun