I have the following type:
std::vector<std::vector<int>> indicies
where the size of the inner vector is always 2. The problem is, that vectors are non-contiguous in memory. I would like to replace the inner vector with something contiguous so that I can cast the flattened array:
int *array_a = (int *) &(a[0][0])
It would be nice if the new type has the [] operator, so that I don't have to change the whole code. (I could also implement it myself if necessary). My ideas are either:
std::vector<std::array<int, 2>>
or
std::vector<std::pair<int, int>>
How do these look in memory? I wrote a small test:
#include <iostream>
#include <array>
#include <vector>
int main(int argc, char *argv[])
{
using namespace std;
vector<array<int, 2>> a(100);
cout << sizeof(array<int, 2>) << endl;
for(auto i = 0; i < 10; i++){
for(auto j = 0; j < 2; j++){
cout << "a[" << i << "][" << j << "] "
<<&(a[i][j]) << endl;
}
}
return 0;
}
which results in:
8
a[0][0] 0x1b72c20
a[0][1] 0x1b72c24
a[1][0] 0x1b72c28
a[1][1] 0x1b72c2c
a[2][0] 0x1b72c30
a[2][1] 0x1b72c34
a[3][0] 0x1b72c38
a[3][1] 0x1b72c3c
a[4][0] 0x1b72c40
a[4][1] 0x1b72c44
a[5][0] 0x1b72c48
a[5][1] 0x1b72c4c
a[6][0] 0x1b72c50
a[6][1] 0x1b72c54
a[7][0] 0x1b72c58
a[7][1] 0x1b72c5c
a[8][0] 0x1b72c60
a[8][1] 0x1b72c64
a[9][0] 0x1b72c68
a[9][1] 0x1b72c6c
It seems to work in this case. Is this behavior in the standard or just a lucky coincidence? Is there a better way to do this?
Vectors are assigned memory in blocks of contiguous locations. When the memory allocated for the vector falls short of storing new elements, a new memory block is allocated to vector and all elements are copied from the old location to the new location. This reallocation of elements helps vectors to grow when required.
Vectors are efficient and flexible. They do require a little more memory than arrays, but this tradeoff is almost always worth the benefits.
clear() don't release or reallocate allocated memory, they just resize vector to zero size, leaving capacity same.
An std::vector manages its own memory. You can use the reserve() and resize() methods to have it allocate enough memory to fit a given amount of items: std::vector<int> vec1; vec1. reserve(30); // Allocate space for 30 items, but vec1 is still empty.
An array<int,2>
is going to be a struct containing an array int[2]
; the standard does not directly mandate it, but there really is no other sane and practical way to do it.
See 23.3.7 [array] within the standard. There is nothing in the standard I can find that requires sizeof(std::array<char, 10>)==1024
to be false. It would be a ridiculous QOI (quality of implementation); every implementation I have seen has sizeof(std::array<T,N>) == N*sizeof(T)
, and anything else I would consider hostile.
Arrays must be contiguous containers which are aggregates that can be initialized by up to N
arguments of types convertible to T
.
The standard permits padding after such an array. I am aware of 0 compilers who insert such padding.
A buffer of contiguous std::array<int,2>
is not guaranteed to be safely accessed as a flat buffer of int
. In fact, aliasing rules almost certainly ban such access as undefined behaviour. You cannot even do this with a int[3][7]
! See this SO question and answer, and here, and here.
Most compilers will make what you describe work, but the optimizer might decide that access through an int*
and through the array<int,2>*
cannot access the same memory, and generate insane results. It does not seem worth it.
A standards compliant approach would be to write an array view type (that takes two pointers and forms an iterable range with []
overloaded). Then write a 2d view of a flat buffer, with the lower dimension either a runtime or compile time value. Its []
would then return an array view.
There is going to be code in boost
and other "standard extension" libraries to do this for you.
Merge the 2d view with a type owning a vector, and you get your 2d vector.
The only behaviour difference is that when the old vector of vector code copies the lower dimension (like auto inner=outer[i]
) it copies data, afer it will instead create a view.
Is there a better way to do this?
I recently finished yet-another-version of Game-of-Life.
The game board is 2d, and yes, the vector of vectors has wasted space in it.
In my recent effort I chose to try a 1d vector for the 2d game board.
typedef std::vector<Cell_t*> GameBoard_t;
Then I created a simple indexing function, for when use of row/col added to the code's readability:
inline size_t gbIndx(int row, int col)
{ return ((row * MAXCOL) + col); }
Example: accessing row 27, col 33:
Cell_t* cell = gameBoard[ gbIndx(27, 33) ];
All the Cell_t* in gameBoard are now packed back to back (definition of vector) and trivial to access (initialize, display, etc) in row/col order using gbIndx().
In addition, I could use the simple index for various efforts:
void setAliveRandom(const GameBoard_t& gameBoard)
{
GameBoard_t myVec(m_gameBoard); // copy cell vector
time_t seed = std::chrono::system_clock::
now().time_since_epoch().count();
// randomize copy's element order
std::shuffle (myVec.begin(), myVec.end(), std::default_random_engine(seed));
int count = 0;
for ( auto it : myVec )
{
if (count & 1) it->setAlive(); // touch odd elements
count += 1;
}
}
I was surprised by how often I did not need row/col indexing.
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