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I am working with weatherAUS dataset that is avaiable in the R libraries. I am trying to replace "Yes" to 1 and "No" to 0 in the RainTomorrow column.
I wrote this but it doesn't seem to work:
weather4$RainTomorrow[weather4$RainTomorrow=="Yes"]<-1
I just says:
Warning message: In
[<-.factor(*tmp*, weather4$RainTomorrow == "Yes", value = c(NA, : invalid factor level, NA generated
What does it mean and what should I do? I reckon I should use as.numeric or as.factor somewhere but I don't know how really.
400
Replace NA values with 0 using is.na() If it is NA, it will return TRUE , otherwise FALSE . So by specifying it inside-[] (index), it will return NA and assigns it to 0. In this way, we can replace NA values with Zero(0) in an R DataFrame. In the above output, we can see that NA values are replaced with 0's.
To replace a column value in R use square bracket notation df[] , By using this you can update values on a single column or on all columns. To refer to a single column use df$column_name .
Replacing values in a data frame is a very handy option available in R for data analysis. Using replace() in R, you can switch NA, 0, and negative values with appropriate to clear up large datasets for analysis.
Using R replace() function to update 0 with NA R has a built-in function called replace() that replaces values in a vector with another value, for example, zeros with NAs.
You can easily do this with dplyr.
require(dplyr)
weather4 <- weather4 %>%
mutate(RainToday = ifelse(RainToday == "No",0,1))
Hope this helps
81
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