I would like to replace values in a vector (x
) with values from another vector (y
). Catch 22: The methods needs to be dynamic to accommodate different number of "levels" in vector x
. For instance, consider vector x
x <- sample(c(1, 2, 3, 4, 5), 100, replace = TRUE)
> x
[1] 2 4 1 1 3 1 1 1 1 1 2 2 5 5 4 5 5 3 4 1 2 2 3 3 3 5 1 3 4 5 5 3 2 4 3 1 3
[38] 1 4 5 4 1 4 5 4 5 2 4 2 5 3 4 3 1 2 1 1 5 1 4 2 2 5 2 2 4 5 2 4 5 2 5 4 1
[75] 3 3 4 4 1 1 4 4 2 4 5 4 5 5 4 2 5 2 4 5 3 2 1 1 2 2
where I would like to replace 1s with 100, 2s with 200 and so on.
This can be done easily with a for loop but for large vectors, several 100 thousand values, this is highly inefficient. Any tips how to optimize the code?
x <- sample(c(1, 2, 3, 4, 5), 100, replace = TRUE)
y <- c(100, 200, 300, 400, 500)
x.lvl <- c(1, 2, 3, 4, 5)
x.temp <- x
for (i in 1:length(y)) {
x.temp[which(x == x.lvl[i])] <- y[i]
}
To replace a value in an R vector, we can use replace function. It is better to save the replacement with a new object, even if you name that new object same as the original, otherwise the replacements will not work with further analysis.
Replace the Elements of a Vector in R Programming – replace() Function. replace() function in R Language is used to replace the values in the specified string vector x with indices given in list by those given in values.
The best option to conditionally replace values in a vector in C++ is using the std::replace_if function. It assigns a new value to all the elements in the specified range for which the provided predicate holds true . For example, the following code replaces all values greater than 5 with 10.
There are different ways of assigning vectors. In R, this task can be performed using c() or using “:” or using seq() function. Generally, vectors in R are assigned using c() function. In R, to create a vector of consecutive values “:” operator is used.
Try with match
y[match(x, x.lvl)]
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