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I have a long string. I want to replace all the matches with part of the matching regex (group).
For example:
String = "This is a great day, is it not? If there is something, THIS IS it. <b>is</b>".
I want to replace all the words "is" by, let's say, "<h1>is</h1>". The case should remain the same as original. So the final string I want is:
This <h1>is</h1> a great day, <h1>is</h1> it not? If there <h1>is</h1> something,
THIS <h1>IS</h1> it. <b><h1>is</h1></b>.
The regex I was trying:
Pattern pattern = Pattern.compile("[.>, ](is)[.<, ]", Pattern.CASE_INSENSITIVE);
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The \[[^\]]*]\[ matches [ , then any 0+ chars other than ] and then ][ . The (...) forms a capturing group #1, it will remember the value that you will be able to get into the replacement with $1 backreference. [^\]]* matches 0+ chars other than ] and this will be replaced.
To use RegEx, the first argument of replace will be replaced with regex syntax, for example /regex/ . This syntax serves as a pattern where any parts of the string that match it will be replaced with the new substring. The string 3foobar4 matches the regex /\d. *\d/ , so it is replaced.
$ means "Match the end of the string" (the position after the last character in the string).
The Regex. Replace(String, String, MatchEvaluator, RegexOptions) method is useful for replacing a regular expression match in if any of the following conditions is true: The replacement string cannot readily be specified by a regular expression replacement pattern.
Like this:
str = str.replaceAll(yourRegex, "<h1>$1</h1>");
The $1 refers to the text captured by group #1 in your regex.
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