Replace letters in string with a dictionary array set in Javascript

Question

I have a string called

"Pizza2Day!"

that I want to replace using a array set. In this array set I have the original alphabets as reference

var originalValues = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'];

and then I have the encryption key set

var encryptedValues = ['m', 'h', 't', 'f', 'g', 'k', 'b', 'p', 'j', 'w', 'e', 'r', 'q', 's', 'l', 'n', 'i', 'u', 'o', 'x', 'z', 'y', 'v', 'd', 'c', 'a'];

what I want to do is find any occurrences in the original string "Pizza2Day" of normal alphabets (a,b,c,d) and replace them with their substitutes in the encryption set (m,n,h,f). So the result would be "Njaam2Fmc!"

How would I go about doing this? Will a loop come in handy in this case?

Answer 1

Another approach.

var dictionary = { "a": "m", "b": "h", "c": "t", "d": "f", "e": "g", "f": "k", "g": "b", "h": "p", "i": "j", "j": "w", "k": "e", "l": "r", "m": "q", "n": "s", "o": "l", "p": "n", "q": "i", "r": "u", "s": "o", "t": "x", "u": "z", "v": "y", "w": "v", "x": "d", "y": "c", "z": "a", "A": "M", "B": "H", "C": "T", "D": "F", "E": "G", "F": "K", "G": "B", "H": "P", "I": "J", "J": "W", "K": "E", "L": "R", "M": "Q", "N": "S", "O": "L", "P": "N", "Q": "I", "R": "U", "S": "O", "T": "X", "U": "Z", "V": "Y", "W": "V", "X": "D", "Y": "C", "Z": "A" },
    string = "Pizza2Day!",
    result = string.replace(/[a-z]/gi, m => dictionary[m]);
    
    console.log(result);