Lets say I have:
a = r''' Example
This is a very annoying string
that takes up multiple lines
and h@s a// kind{s} of stupid symbols in it
ok String'''
I need a way to do a replace(or just delete) and text in between "This" and "ok" so that when I call it, a now equals:
a = "Example String"
I can't find any wildcards that seem to work. Any help is much appreciated.
A character in Python is also a string. So, we can use the replace() method to replace multiple characters in a string. It replaced all the occurrences of, Character 's' with 'X'.
Python String replace() Method The replace() method replaces a specified phrase with another specified phrase. Note: All occurrences of the specified phrase will be replaced, if nothing else is specified.
sub() function belongs to the Regular Expressions ( re ) module in Python. It returns a string where all matching occurrences of the specified pattern are replaced by the replace string. To use this function, we need to import the re module first.
What is the string replace() method in Python? The replace() method is a built-in functionality offered in Python programming. It replaces all the occurrences of the old substring with the new substring. Replace() returns a new string in which old substring is replaced with the new substring.
We will use two functions of the regex module- re.sub () and re.subn () to replace multiple substrings in a string. sub () - It replaces the contents of a string based on patterns. It takes a pattern or a string as the first argument.
Use re.sub: It replaces the text between two charactersor symbolsor stringswith desired characteror symbolor string. format: re.sub('A?(.*?)B', P, Q, flags=re.DOTALL)
Replace all occurrences of a character in a string To replace all the occurrences of a character with a new character, we simply have to pass the old character and the new character as input to the replace() method when it is invoked on the string. You can observe this in the following example.
This problem can be solved using the nested replace method, which internally would create a temp. variable to hold the intermediate replacement state. The original string is : abbabba The string after replacement of positions : baabaab
You need Regular Expression
:
>>> import re
>>> re.sub('\nThis.*?ok','',a, flags=re.DOTALL)
' Example String'
Another method is to use string splits:
def replaceTextBetween(originalText, delimeterA, delimterB, replacementText):
leadingText = originalText.split(delimeterA)[0]
trailingText = originalText.split(delimterB)[1]
return leadingText + delimeterA + replacementText + delimterB + trailingText
Limitations:
The DOTALL flag is the key. Ordinarily, the '.' character doesn't match newlines, so you don't match across lines in a string. If you set the DOTALL flag, re will match '.*' across as many lines as it needs to.
a=re.sub('This.*ok','',a,flags=re.DOTALL)
Use re.sub
: It replaces the text between two characters or symbols or strings with desired character or symbol or string.
format: re.sub('A?(.*?)B', P, Q, flags=re.DOTALL)
where A : character or symbol or string B : character or symbol or string P : character or symbol or string which replaces the text between A and B Q : input string re.DOTALL : to match across all lines
import re
re.sub('\nThis?(.*?)ok', '', a, flags=re.DOTALL)
output : ' Example String'
Lets see an example with html code as input
input_string = '''<body> <h1>Heading</h1> <p>Paragraph</p><b>bold text</b></body>'''
Target : remove <p>
tag
re.sub('<p>?(.*?)</p>', '', input_string, flags=re.DOTALL)
output : '<body> <h1>Heading</h1> <b>bold text</b></body>'
Target : replace <p>
tag with word : test
re.sub('<p>?(.*?)</p>', 'test', input_string, flags=re.DOTALL)
otput : '<body> <h1>Heading</h1> test<b>bold text</b></body>'
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