Replace all instances of a pattern with regular expressions in Javascript / jQuery

Question

First off I don't know much about regex and need to buy a book because it's has proven to me to be difficult to pickup.

Ultimately I want to take a dom element, and replace text within straight brackets "[" and "]" and insert a link around the text, and there may be multiple bracket sets in the string.

function changeTip() {  
        var link = '<a href="' + $('#txtURL').attr('value') + '" target="_blank">';
        $('.tipoftheweektip').html($('#txtTip').attr("value").replace('[', link).replace(']', '</a>'));
    }

This works except:

• doesnt work on the second set of brackets
• if there isnt a closing straight bracket, it deletes all the text before the opening straight bracket

I've looked at examples and because straight brackets are used in the regex code, I cant figure out how to look for a bracket and replace it.

Anyone out there that has done something similar that they can share? Thanks in advance.

Answer 1

.replace(/\[([^\]]*)\]/g, link + "$1</a>")

which means, find text between [ and ] and replace it with the value of link, the text itself and ''. This ensures matching square brackets. The 'g' means 'do it multiple times (globally)'.