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This seems like an easy one (and it probably is), but since I'm braindead, I'm ready to get on the shame wall.
How to copy a list object n times, and wrap it up in a list afterwards? Something like this:
list(foo = "", bar = 0) in order to get:
list( list(foo = "", bar = 0), list(foo = "", bar = 0) ) 
988
To repeat the elements of the list n times, we will first copy the existing list into a temporary list. After that, we will add the elements of the temporary list to the original list n times using a for loop, range() method, and the append() method.
Use the multiplication operator to create a list with the same value repeated N times in Python, e.g. my_list = ['abc'] * 3 . The result of the expression will be a new list that contains the specified value N times. Copied!
The replication of list of a list can be created by using rep function. For example, if we have a list called x and we want to create five times replicated list of this list then we can use the code rep(list(x),5).
To create a list with a single item repeated N times with Python, we can use the * operator with a list and the number of items to repeat. We define my_list by using an list and 10 as an operand to return a list with 'foo' repeated 10 times.
Well, rep works (and is "vectorized") if you simply wrap the list in another list...
x <- list(foo = "", bar = 0) rep(list(x), 2) That trick can also be used to assign NULL to an element in a list:
x[2] <- list(NULL) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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