In my dataframe I have some categorical columns with over 100 different categories. I want to rank the categories by the most frequent. I keep the first 9 most frequent categories and the less frequent categories rename them automatically by: OTHER
Example:
Here my df :
print(df)
Employee_number Jobrol
0 1 Sales Executive
1 2 Research Scientist
2 3 Laboratory Technician
3 4 Sales Executive
4 5 Research Scientist
5 6 Laboratory Technician
6 7 Sales Executive
7 8 Research Scientist
8 9 Laboratory Technician
9 10 Sales Executive
10 11 Research Scientist
11 12 Laboratory Technician
12 13 Sales Executive
13 14 Research Scientist
14 15 Laboratory Technician
15 16 Sales Executive
16 17 Research Scientist
17 18 Research Scientist
18 19 Manager
19 20 Human Resources
20 21 Sales Executive
valCount = df['Jobrol'].value_counts()
valCount
Sales Executive 7
Research Scientist 7
Laboratory Technician 5
Manager 1
Human Resources 1
I keep the first 3 categories then I rename the rest by "OTHER", how should I proceed?
Thanks.
rename_categories() function. The rename_categories() function is used to rename categories. list-like: all items must be unique and the number of items in the new categories must match the existing number of categories. dict-like: specifies a mapping from old categories to new.
You can use the rename() method of pandas. DataFrame to change column/index name individually. Specify the original name and the new name in dict like {original name: new name} to columns / index parameter of rename() .
Convert your series to categorical, extract categories whose counts are not in the top 3, add a new category e.g. 'Other'
, then replace the previously calculated categories:
df['Jobrol'] = df['Jobrol'].astype('category')
others = df['Jobrol'].value_counts().index[3:]
label = 'Other'
df['Jobrol'] = df['Jobrol'].cat.add_categories([label])
df['Jobrol'] = df['Jobrol'].replace(others, label)
Note: It's tempting to combine categories by renaming them via df['Jobrol'].cat.rename_categories(dict.fromkeys(others, label))
, but this won't work as this will imply multiple identically labeled categories, which isn't possible.
The above solution can be adapted to filter by count. For example, to include only categories with a count of 1 you can define others
as so:
counts = df['Jobrol'].value_counts()
others = counts[counts == 1].index
Use value_counts
with numpy.where
:
need = df['Jobrol'].value_counts().index[:3]
df['Jobrol'] = np.where(df['Jobrol'].isin(need), df['Jobrol'], 'OTHER')
valCount = df['Jobrol'].value_counts()
print (valCount)
Research Scientist 7
Sales Executive 7
Laboratory Technician 5
OTHER 2
Name: Jobrol, dtype: int64
Another solution:
N = 3
s = df['Jobrol'].value_counts()
valCount = s.iloc[:N].append(pd.Series(s.iloc[N:].sum(), index=['OTHER']))
print (valCount)
Research Scientist 7
Sales Executive 7
Laboratory Technician 5
OTHER 2
dtype: int64
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