Look at this code.
#include <vector>
template<class ...Args>
using other_vector = std::vector<Args...>;
template<class T>
void f(std::vector<T>& ) {}
template<class T>
void f(other_vector<T>& ) {}
int main()
{
other_vector<int> b;
f(b);
return 0;
}
It does not compile, because f
is being redeclared. I totally understand the error. However, I need a second class that behaves like std::vector<T>
, but will be seen as a different type, so that overloading, like in the above example, would be legal.
What could I do?
std::vector<T>
as a base class. This might work, but one should not inherit from std containers.Any better alternative? C++11 or C++14 allowed.
You might try to mess with the allocator:
template<class T>
struct allocator_wrapper : T { using T::T; };
template<class T, class A = std::allocator<T>>
using other_vector = std::vector<T, allocator_wrapper<A>>;
Live example
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