Removing the array element in mongoDB based on the position of element

Question

Actually I need to remove an element from the array based on its position. Using $pop we can remove element from top or bottom (considering it as a stack. 0th element at top) as explained here.

We can also remove element from array based on the value of the elements in the array using $pull as explained here.

But I need to remove element from the array based on position. So is there any way I can do this.

Answer 1

From documentation:

{ $pull : { field : {$gt: 3} } } removes array elements greater than 3

So i suppose that you can do somethig like this for now:

{ $pull : { field : {$gt: 3, $lt: 5} } } // shoud remove elemet in 4 position 

Or try update using position operator, i suppose shoud be something like this:

  { $pull : "field.4" } 

  { $pull : {"field.$": 4}}

It is only a suggestion, because i can't test it right now.

Update:

Seems you cant do it right know in one step(there is such bug in jira)

But you can remove using unset element in position and that pull elemets with null value:

{$unset : {"array.4" : 1 }}
{$pull : {"array" : null}}