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Greetings,
I am attempting to remove multiple documents from a MongoDB collection using the following syntax. I don't know if this is correct as I found it somewhere on the internet and haven't been able to find anything since enforcing the legitimacy of this statement:
pymongo_collection_object.remove(
[
{
'sku': '100-00'
},
{
'sku': '200-00'
}
]
, safe=True)
I would expect the above code would remove both documents including a 'sku' value of '100-00' or '200-00' but unfortunately both documents are still present within the collection. I also tried casting both the 'sku' key and its value to Unicode as I know they are stored in this encoding. As you can tell I am also enabling safe mode ensuring that there is nothing out of line happening on the server side.
Any help is appreciated, thank you!
682
To delete all documents in a collection, pass an empty document ( {} ). Optional. To limit the deletion to just one document, set to true . Omit to use the default value of false and delete all documents matching the deletion criteria.
Create an index for a MongoDB collection, and specify the order. When you use PyMongo to create an index, you can pair the index name with either a 1 or a -1 integer value to explicitly set the sort order to ascending or descending, respectively.
Find() Method. In MongoDB, find() method is used to select documents in a collection and return a cursor to the selected documents. Cursor means a pointer that points to a document, when we use find() method it returns a pointer on the selected documents and returns one by one.
You can do so by using $or / $in operators.
Try this:
pymongo_collection_object.remove({'$or': [{'sku': '100-00'}, {'sku': '200-00'}]}, safe=True)
or
pymongo_collection_object.remove({'sku': {'$in': ['100-00', '200-00']}}, safe=True)
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