How would I remove the leading zeros from a number which is in the form of varchar. I have tried the following:
Option 1:
insert into example_table (columnName)
(SELECT
SUBSTR(columnName2, InStr('%[^0 ]%', columnName2 + ' '), 10)
from columnName2);
With this, the error I get is
SQL Error: ORA-01722: invalid number
ORA-02063: preceding line from xxxx
01722. 00000 - "invalid number"
Option 2:
insert into example_table (columnName)
(SELECT
SUBSTR(columnName2, InStr('%[^0 ]%', columnName2 + ' '),
LEN(columnName2))
from columnName2);
This time I get
Error at Command Line:23 Column:87
Error report:
SQL Error: ORA-00904: "LEN": invalid identifier
Option 3:
SUBSTRING
(columnName2, PATINDEX('%[^0 ]%', columnName2 + ' '), 10));
Similar to above, I get
Error at Command Line:23 Column:41
Error report:
SQL Error: ORA-00904: "PATINDEX": invalid identifier
00904. 00000 - "%s: invalid identifier"
EDIT
I think that the trim route might be my best option, however... I am uncertain how to use it in the case I have.
INSERT INTO temp_table
(columnNeedTrim, column2, column3, column4, column5)
SELECT * FROM
(SELECT(
SELECT TRIM(leading '0' from columnNeedTrim) FROM table),
table.column2,
table2.column3,
table.column4
table.column5
FROM
table
INNER JOIN
table2 ON
table1.columnNeedTrim=table2.columnNeedTrim)
WHERE NOT EXISTS (SELECT * FROM temp_table);
I now get an error because my trim function returns multiple row result.
Error report:
SQL Error: ORA-01427: single-row subquery returns more than one row
01427. 00000 - "single-row subquery returns more than one row"
I am not sure how to work a trim (or a cast) into the statement above. Any help on that? Thanks for any help!
Basically it performs three steps: Replace each 0 with a space – REPLACE([CustomerKey], '0', ' ') Use the LTRIM string function to trim leading spaces – LTRIM(<Step #1 Result>) Lastly, replace all spaces back to 0 – REPLACE(<Step #2 Result>, ' ', '0')
TRIM enables you to trim leading or trailing characters (or both) from a character string. If trim_character or trim_source is a character literal, then you must enclose it in single quotes. If you specify LEADING , then Oracle Database removes any leading characters equal to trim_character .
Best Answer In any case, to show a NUMBER with leading zeros: select TO_CHAR(3, 'FM000') from dual; will show the string '003'.
Oracle has built-in TRIM
functions for strings. Assuming you have a string like '00012345'
and you want to keep it as a string, not convert it to an actual NUMBER
, you can use the LTRIM
function with the optional second set
parameter specifying that you're triming zeros:
select ltrim('000012345', '0') from dual;
LTRIM
-----
12345
If you might also have leading spaces you can trim both in one go:
select ltrim(' 00012345', '0 ') from dual;
LTRIM
-----
12345
You could also convert to a number and back, but that seems like a lot of work unless you have other formatting that you want to strip out:
select to_char(to_number('000012345')) from dual;
Incidentally, the immediate reason you get the ORA-01722 from your first attempt is that you're using the numeric +
operator instead of Oracle's string concentenation operator ||
. It's doing an implicit conversion of your string to a number, which it seems you're trying to avoid, and the implicit conversion of the single space - whatever that is for - is causing the error. (Possibly some of your values are not, in fact, numbers at all - another example of why numbers should be stored in NUMBER
fields; and if that is the case then converting (or casting) to a number and back would still get the ORA-01722). You'd get the same thing in the second attempt if you were using LENGTH
instead of LEN
. Neither would work anyway as INSTR
doesn't recognise regular expressions. You could use REGEXP_INSTR
instead, but you'd be better off with @schurik's REGEXP_REPLACE
version if you wanted to go down that route.
I'm not sure I understand your question edit. It looks like your insert can be simplified to:
INSERT INTO temp_table (columnNeedTrim, column2, column3, column4, column5)
SELECT LTRIM(table1.columnNeedTrim, '0 '),
table1.column2,
table1.column3,
table1.column4,
table1.column5
FROM table1
INNER JOIN table2 ON table2.columnNeedTrim = table1.columnNeedTrim
WHERE NOT EXISTS (
SELECT * FROM temp_table
WHERE columnNeedTrim = LTRIM(t42.columnNeedTrim, '0 '));
(I don't understand why you're doing a subquery in your version, or why you're getting the trimmed value from another subquery.)
You could also use MERGE
:
MERGE INTO temp_table tt
USING (
SELECT LTRIM(t42.columnNeedTrim, '0 ') AS columnNeedTrim,
t42.column2,
t42.column3,
t42.column4,
t42.column5
FROM t42
INNER JOIN t43 ON t43.columnNeedTrim=t42.columnNeedTrim
) sr
ON (sr.columnNeedTrim = tt.columnNeedTrim)
WHEN NOT MATCHED THEN
INSERT (tt.columnNeedTrim, tt.column2, tt.column3, tt.column4, tt.column5)
VALUES (sr.columnNeedTrim, sr.column2, sr.column3, sr.column4, sr.column5);
For SQL server, if you know the data is actually a number, you can just cast it twice. Casting to an int
removes the leading zeroes, then back to a string for insertion. I'm assuming you can do something similar in Oracle.
DECLARE @vc varchar(100) = '0000000000000000000001234'
SELECT CAST(CAST(@vc as int) as varchar(100))
Returns:
1234
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