I have developed an array list.
ArrayList<String> list = new ArrayList<String>();
list.add("1");
list.add("2");
list.add("3");
list.add("3");
list.add("5");
list.add("6");
list.add("7");
list.add("7");
list.add("1");
list.add("10");
list.add("2");
list.add("12");
But as seen above it contains many duplicate elements. I want to remove all duplicates from that list. For this I think first I need to convert the list into a set.
Does Java provide the functionality of converting a list into a set? Are there other facilities to remove duplicates from a list?
You can convert to a Set with:
Set<String> aSet = new HashSet<String>(list);
Or you can convert to a set and back to a list with:
list = new ArrayList<String>(new HashSet<String>(list));
Both of these, however, are not likely to preserve the order of the elements. To preserve order, you can use a HashSet
as an auxiliary structure while iterating:
List<String> list2 = new ArrayList<String>();
HashSet<String> lookup = new HashSet<String>();
for (String item : list) {
if (lookup.add(item)) {
// Set.add returns false if item is already in the set
list2.add(item);
}
}
list = list2;
In the case of duplicates, only the first occurrence will appear in the result. If you want only the last occurrence to appear, that's a tougher problem. I'd tackle it by reversing the input list, applying the above, and then reversing the result.
This:
Set<String> set = new HashSet<String>();
set.addAll(list);
list.clear();
list.addAll(set);
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