I created a table using migration like:
Schema::create('listings', function (Blueprint $table) {
$table->increments('id');
$table->decimal('original_price', 10, 2);
$table->decimal('discouted_price', 10, 2);
$table->integer('city_id')->index()->unsigned()->nullable();
$table->foreign('city_id')->references('id')->on('cities');
$table->integer('destination_city_id')->unsigned()->index();
$table->foreign('destination_city_id')->references('id')->on('cities');
$table->string('url');
$table->string('titile');
$table->text('description')->nullable();
$table->dateTime('expires_at');
$table->integer('clicks')->default('0');
$table->integer('views')->default('0');
$table->timestamps();
$table->softDeletes();
});
Now i wanna remove this two colums from ('listings').
$table->integer('city_id')->index()->unsigned()->nullable();
$table->foreign('city_id')->references('id')->on('cities');
$table->integer('destination_city_id')->unsigned()->index();
$table->foreign('destination_city_id')->references('id')->on('cities');
But someone can write the this new migration how must look for remove on this two columns ?
The function for hasColumn in Laravel Schema Builder in L5.8 is as follows:
\vendor\laravel\framework\src\Illuminate\Database\Schema\Builder::hasColumn($table,$column)
{
return in_array(
strtolower($column), array_map('strtolower',$this->getColumnListing($table)));
so you should use your table name as the first parameter, like this
public function up() {
if(Schema::hasColumn('listings','city_id')) {
Schema::table('listings',function (Blueprint $table) {
$table->dropColumn('city_id');
});
}
}
repeat for each column that you wish to drop
You can do like this,
if (Schema::hasColumn('city_id', 'destination_city_id'))
{
$table->dropForeign('city_id');
$table->dropForeign('destination_city_id');
$table->dropColumn(['city_id', 'destination_city_id']);
}
Its always better to check if relavant column exists in table.
Give it a try, this should work.
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