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Am doing a simple android application.In that I am deleting an element from array using the following code.
arr_fav = {"1","2","3"};
for(int i= 0;i<arr_fav.length;i++)
{
if(current_id == Integer.parseInt(arr_fav[i]))
{
arr_fav[1] = null;
} }
By doing this am getting the array like arr_fav = {"1",null,"3"}.But I want like arr_fav = {"1","3"}.How to delete an element.Am new to this android development.Please help me to solve this.
391
You can remove the element at any index by using the splice method. If you have an array named arr it can be used in this way to remove an element at any index: arr. splice(n, 1) , with n being the index of the element to remove.
If you want to remove an item from an array, you can use the pop() method to remove the last element or the shift() method to remove the first element.
How do you remove the first element from an array in Kotlin? Using removeAt() function. The removeAt() function removes an element at the specified index from a mutable list. Using clear() function.
its better to use arraylist
arr_fav = {"1","2","3"};
List<String> numlist = new ArrayList<String>();
for(int i= 0;i<arr_fav.length;i++)
{
if(current_id == Integer.parseInt(arr_fav[i]))
{
// No operation here
}
else
{
numlist.add(arr_fav[i]);
}
}
arr_fav = numlist .toArray(new String[numlist .size()]);
You don't.
Arrays can not be resized.
You would need to create a new (smaller) array, and copy the elements you wished to preserve into it.
A better Idea would be to use a List implementation that was dynamic. An ArrayList<Integer> for example.
42
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