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I have Strings (from DB), which may contain numeric values. If it contains numeric values, I'd like to remove trailing zeros such as:
10.000010.234000 str.replaceAll("\\.0*$", ""), works on the first one, but not the second one.
A lot of the answers point to use BigDecimal, but the String I get may not be numeric. So I think a better solution probably is through the Regex.
863
stripTrailingZeros() is an inbuilt method in Java that returns a BigDecimal which is numerically equal to this one but with any trailing zeros removed from the representation. So basically the function trims off the trailing zero from the BigDecimal value.
Algorithm. Step 1: Get the string Step 2: Count number of trailing zeros n Step 3: Remove n characters from the beginning Step 4: return remaining string.
Java For Testers The replaceAll() method of the String class accepts two strings representing a regular expression and a replacement String and replaces the matched values with given String. The ^0+(?! $)"; To remove the leading zeros from a string pass this as first parameter and “” as second parameter.
Using StringBuildersetLength() instead of StringBuilder. deleteCharAt() when we remove trailing zeroes because it also deletes the last few characters and it's more performant.
there are possibilities:
1000 -> 1000 10.000 -> 10 (without point in result) 10.0100 -> 10.01 10.1234 -> 10.1234 I am lazy and stupid, just
s = s.indexOf(".") < 0 ? s : s.replaceAll("0*$", "").replaceAll("\\.$", ""); Same solution using contains instead of indexOf as mentioned in some of the comments for easy understanding
s = s.contains(".") ? s.replaceAll("0*$","").replaceAll("\\.$","") : s If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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