Remove everything in string up to last forward slash [duplicate]

Question

I have a string like this:

"vehicles/vehicle_type/filename.csv"

I just want to be left with:

"filename.csv"

I have tried this:

sub('/^(.*[\\\/])/', "", the_string)

But get an "unrecognized escape in character string" error

Answer 1

To grab the end of a file path, you could use simply basename().

x <- "vehicles/vehicle_type/filename.csv"
basename(x)
# [1] "filename.csv"

Or if you'd like to continue using regex, adjust your sub() call to

sub(".*/", "", x)
# [1] "filename.csv"

.* removes everything, so .*/ removes everything up to and including the final / (because the previous one was included in the "everything").