Remove array elements that are present in another array

Question

There is a list of words and list of banned words. I want to go through the word list and redact all the banned words. This is what I ended up doing (notice the catched boolean):

puts "Give input text:"
text = gets.chomp
puts "Give redacted word:"
redacted = gets.chomp

words = text.split(" ")
redacted = redacted.split(" ")
catched = false

words.each do |word|
  redacted.each do |redacted_word|
    if word == redacted_word
        catched = true
        print "REDACTED "
        break
    end
  end
    if catched == true
        catched = false
    else
        print word + " "
    end
end

Is there any proper/efficient way?

Answer 1

You can use .reject to exclude all banned words that are present in the redacted array:

words.reject {|w| redacted.include? w}

Demo

If you want to get the list of banned words that are present in the words array, you can use .select:

words.select {|w| redacted.include? w}

Demo

Answer 2

It also can works.

words - redacted

+, -, &, these methods are very simple and useful.

irb(main):016:0> words = ["a", "b", "a", "c"]
=> ["a", "b", "a", "c"]
irb(main):017:0> redacted = ["a", "b"]
=> ["a", "b"]
irb(main):018:0> words - redacted
=> ["c"]
irb(main):019:0> words + redacted
=> ["a", "b", "a", "c", "a", "b"]
irb(main):020:0> words & redacted
=> ["a", "b"]