I'm working with a long named list and I'm trying to keep/remove elements that match a certain name, within a tidyverse context, similar to
dplyr::select(contains("pattern"))
However, I'm having issues figuring it out.
library(tidyverse)
a_list <-
list(a = "asdfg",
b = "qwerty",
c = "zxcvb")
a_list %>% pluck("a") # works
a_list %>% pluck(contains("a")) #does not work
a_list[2:3] # this is what I want
a_list %>% pluck(-"a") # but this does not work
Remove an item by value: remove() You can remove the first item from the list where its value is equal to the specified value with remove() . If the list contains more than one matching the specified value, only the first is deleted.
How to Remove an Element from a List Using the remove() Method in Python. To remove an element from a list using the remove() method, specify the value of that element and pass it as an argument to the method. remove() will search the list to find it and remove it.
You can use the pop() method to remove specific elements of a list. pop() method takes the index value as a parameter and removes the element at the specified index. Therefore, a[2] contains 3 and pop() removes and returns the same as output.
To remove by name you could use:
a_list %>% purrr::list_modify("a" = NULL)
$`b`
[1] "qwerty"
$c
[1] "zxcvb"
I'm not sure the other answers are using the name of the element, rather than the element itself for selection. The example you gave is slightly confusing since the element 'a' both contains 'a' in it's value AND is called 'a'. So it's easy to get mixed up. To show the difference I'll modify the example slightly.
b_list <-
list(a = "bsdfg",
b = "awerty",
c = "zxcvb")
b_list %>% purrr::list_modify("a" = NULL)
returns
$`b`
[1] "awerty"
$c
[1] "zxcvb"
but
purrr::discard(b_list,.p = ~stringr::str_detect(.x,"a"))
returns
$`a`
[1] "bsdfg"
$c
[1] "zxcvb"
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