Remove all elements from array that match specific string

Question

What is the easiest way to remove all elements from array that match specific string? For example:

array = [1,2,'deleted',4,5,'deleted',6,7];

I want to remove all 'deleted' from the array.

Answer 1

Simply use the Array.prototype.filter() function for obtain elements of a condition

var array = [1,2,'deleted',4,5,'deleted',6,7]; var newarr = array.filter(function(a){return a !== 'deleted'}) 

Update: ES6 Syntax

let array = [1,2,'deleted',4,5,'deleted',6,7] let newarr = array.filter(a => a !== 'deleted') 

Answer 2

If you have multiple strings to remove from main array, You can try this

// Your main array  var arr = [ '8','abc','b','c'];  // This array contains strings that needs to be removed from main array var removeStr = [ 'abc' , '8'];  arr = arr.filter(function(val){   return (removeStr.indexOf(val) == -1 ? true : false) })  console.log(arr);  // 'arr' Outputs to : [ 'b', 'c' ] 

OR

Better Performance(Using hash) , If strict type equality not required

// Your main array  var arr = [ '8','deleted','b','c'];  // This array contains strings that needs to be removed from main array var removeStr = [ 'deleted' , '8']; var removeObj = {};  // Use of hash will boost performance for larger arrays removeStr.forEach( e => removeObj[e] = true);  var res = arr.filter(function(val){   return !removeObj[val] })  console.log(res);  // 'arr' Outputs to : [ 'b', 'c' ]