So I have a dataset in R with the following layout as an example:
ID Date Tally
1 2/1/2011 1
2 2/1/2011 2
3 2/1/2011 3
1 2/1/2011 4
2 2/1/2011 5
1 2/1/2011 6
3 2/1/2011 7
4 2/1/2011 8
2 2/1/2011 9
I want to remove all instances except the LAST instance of the post id. Right now everything I can find online, and functions I am using is removing everything except the FIRST instance.
So my new data frame would look like:
ID Date Tally
1 2/1/2011 6
3 2/1/2011 7
4 2/1/2011 8
2 2/1/2011 9
How do I do this? Right now I am only able to keep the first instance. I want it to do the opposite? Any help?
When duplicates are removed, the first occurrence of the value in the list is kept, but other identical values are deleted. Because you are permanently deleting data, it's a good idea to copy the original range of cells or table to another worksheet or workbook before removing duplicate values.
Wouldn't this just be the standard case for using the 'fromLast' parameter to duplicated
?
dat[ !duplicated(dat[, c("ID", "Date")], fromLast=T),]
#---------
ID Date Tally
6 1 2/1/2011 6
7 3 2/1/2011 7
8 4 2/1/2011 8
9 2 2/1/2011 9
Your example was not rich enough to tell whether you needed the "Date" column in the test fro duplication, so perhaps you could simplify. I'm leaving it in to illustrate that duplicated
has a data.frame method. I prefer !duplicated
to unique
because it allows easy access to the set complement if you are comparing groups.
Use !rev(duplicated(rev(ID)))
to filter out all but the last unique occurrences.
To get the dataset filtered, use dataset[!rev(duplicated(rev(dataset$ID))),]
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